What is the positive solution of |2x-6|=9?
1 answer:
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Answer:
The answers are a) 1/3 and b) 1/3
Step-by-step explanation:
we will consider t to be the arrival time variable in minutes. We will have it run from 0 min to 30 min omitting the 7 hours , which won't change the results since the PDF we are about to calculate is a constant.
So the PDF of the arrival time is a constant and the since the area under this PDF distribution should be equal to 1 so, Let the height of the constant distribution equal to c, so c*30 (which is equal to the total probability) would be the area under the distribution, but this area should be equal to 1, So that gives us c=1/30 which is the value of the constant PDF for all corresponding arrival times.
part a) of the question asks for the probability that the passengers wait less than 5 minute. The passengers would have to wait for the bus 5 min or late if they arrive between the times (10 - 15 )min and (25 - 30) min. So we will have to integrate the PDF corresponding to these times and then we will will just have to add the probabilities calculated as give below,
Now part b) of the question asks for the probability that the passenger waits for more than 10 minutes. Which can be calculated by noting that that can only happen if the passenger arrives between the times (0 - 5) min and (15 - 20) min. So we will have to integrate the PDF corresponding to these times and then we will will just have to add the probabilities calculated as give below,
The answer to part b) is 1/3.
Answer: There are 32 students who like brussels sprouts but dislike beans.
Step-by-step explanation:
Since we have given that
Number of students eat in the cafeteria = 120
Fraction dislike lime beans =
Fraction who dislike lime beans and brussles sprouts both =
Fraction who dislikes lime beans but not brussles is given by
So, Number of students who like brussels sprouts but dislike lima beans is given by
Hence, there are 32 students who like brussels sprouts but dislike beans.
Answer:
The sample space for selecting the group to test contains <u>2,300</u> elementary events.
Step-by-step explanation:
There are a total of <em>N</em> = 25 aluminum castings.
Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).
It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.
In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.
The formula to compute the combinations of k items from n is given by the formula:
Compute the number of samples that are possible as follows:
The sample space for selecting the group to test contains <u>2,300</u> elementary events.