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krek1111 [17]
2 years ago
15

Which graph shows the same end behavior as the graph of f(x) = 2x6 – 2x2 – 5?

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
3 0

The graph that shows the same end behavior as the graph of f(x) = 2x⁶ – 2x² – 5 is graph A.

<h3>How to explain the graph?</h3>

In order to find the end behavior of the graph, we need to find the degree of the given function and the leading coefficient. The highest power of x is 6.

The leading coefficient is the coefficient of the highest power term. We have the highest power term is 2x⁶. The leading coefficient is 2 (Positive number)

Therefore, The graph that shows the same end behavior as the graph of f(x) = 2x⁶ – 2x² – 5 is graph A.

Learn more about graph on:

brainly.com/question/19040584

#SPJ1

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Find 356*27+537*373-235*73=
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Answer:

Using PEMDAS the answer would be 192758

Step-by-step explanation:

(356*27)+(537*373)-(235*73)=

9612+200301-17155=

Solve

192758

Happy learning!

--Applepi101

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Sarah bought a binder for $7.25 and six folders that totaled $9.05. How much did each folder cost?
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a garden table and bench cost $738 combined the garden table costs $88 more than the bench what is the cost of the bench
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Hello 

the answer to this is 

650

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Write 0.000 000 33 in scientific notation.
jarptica [38.1K]

<span>Number part = <span>3.3 </span></span>and

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<span>3.3*<span>10<span>−7</span></span></span>

7 0
3 years ago
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A stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer. If the top laye
Svetlanka [38]

Answer:  The total number of logs in the pile is 6.

Step-by-step explanation:  Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two​ logs.

We are to find the total number of logs in the pile.

Let n represents the total number of logs in the pile.

Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with

first term, a = 32  and  common difference, d = -6.

We know that

the n-th term of an arithmetic sequence with first term a and common difference d is

a_n=a+(n-10)d.

Since there are n logs in the pile, so we get

a+(n-1)d=2\\\\\Rightarrow 32+(n-1)(-6)=2\\\\\Rightarrow 32-6n+6=2\\\\\Rightarrow 6n=36\\\\\Rightarrow n=6.

Thus, the total number of logs in the pile is 6.

6 0
3 years ago
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