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2 years ago

20) What is the minimum energy required to ionize a hydrogen atom in the n = 2 state?

Physics

1 answer:

Vedmedyk [2.9K]2 years ago

8 0

The minimum energy required to ionize a hydrogen atom in the n = 2 state is -1.51 eV. Option B is corect.

<h3>What is hydrogen?</h3>

The chemical element hydrogen has the atomic number 1 and the symbol H. The smallest element is hydrogen.

The second excited state matches n=3. The minimum energy required to ionize a hydrogen atom in the n = 2 state is;

$\rm E= - \frac{13.6}{n^2} \\\\ \rm E= \frac{13.6}{3^2} \\\\ E= - \frac{13.6}{9} \\\\ E= -1.51 \ eV$

The minimum energy required to ionize a hydrogen atom in the n = 2 state is -1.51 eV

Hence, option B is corect.

To learn more about the hydrogen refer to:

brainly.com/question/11837837

#SPJ1

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Answer:

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Explanation:

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