Answer:
Force exerted, F = 1.5 N
Explanation:
It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.
i.e. u = 0
v = 30 m/s
Time taken, t = 0.06 s
Mass of the paper, m = 0.003 kg
We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :
F = 1.5 N
So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.
We have that the sea level pressure for Leh area is 1150mb mathematically given as
Ps= 1150 mb
<h3>
Sea level pressure</h3>
Question Parameters:
Ladakh is 800 mb.
<u>assuming </u>that Leh is at an altitude of 3500 m and every 100 m
increase in height with respect to sea level corresponds to 10 mb pressure,
Generally, for 3500m the pressure change will be 350 mb.
Therefore, here for the sea level <em>pressure</em> we need to add,
Ps=800+350
Ps= 1150 mb
For more information on Pressure visit
brainly.com/question/25688500
Answer:
Explanation:
- The radio waves have a fixed relationship between the propagation speed (the speed of light in vacuum), the frequency and the wavelength, as follows:
- v = c = λ*f
where c= speed of light in vacuum = 3*10⁸ m/s, λ = wavelength =
4.92*10⁷ m.
Solving for f, we get the frequency of the radio waves:
f = 6.1 Hz
- Now, from the Hooke's law, we know that the mass attached at the end of the spring oscillates with an angular frequency defined by a fixed relationship between the spring constant k and the mass m, as follows:
- Now, we know that there exists a fixed relationship between the angular frequency and the frequency, as follows:
- We also know that f in (2) is the same that we got for the radio waves, so replacing (2) in (1), and rearranging terms, we can solve for k, as follows:
27.5 because of you divide the 55miles with the time you get your velocity which is the speed.
Answer:
it depends on a person's own weight
