Answer:
The student hears the wave that is transmitted by the desk
Explanation:
Mechanical waves need a material medium to be able to be transmitted, in the case of sound waves, one of the most common media is air, but it is also transmitted in other media in this case, stationery is transmitted.
The student hears the wave that is transmitted by the desk
The speed of the wave is proportional to the density of the material, so the wave that the student hears arrives much faster through the desk than through the air
Answer:
<h2>2.35 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
force = 0.49 × 4.8 = 2.352
We have the final answer as
<h3>2.35 N</h3>
Hope this helps you
Answer:
The positively charged ball moves between both charged plates till the plates and the ball all become neutral.
Check Explanation for more.
Explanation:
Let the ball be in square brackets, and the plates in normal brackets.
(+) [+] (-)
From the law that like charges repel and unlike charges attract.
The positive ball would go first to the negatively charged plate. After which, the ball would hold more negative charges overall than before.
Because the ball is now more negatively charged, it then travels towards the positive plate. In the same manner, the ball would transfer negative electrons to the positive plate.
So, when leaving the positive plate, the ball would be more positive and be drawn towards the negative plate once more. In doing so, it would make the negative plate more positive.
Then, the ball again holds more negative electrons and is drawn towards the positive plate once more.
This back and forth process continues until the once-positive and once-negative plates become neutral, that is, they are discharged.
The ball hanging on the insulated thread becomes neutral too at this point.
Hope this Helps!!!
Answer:
a) 48.5 ft/s
b) 36.5 ft
c) -80.3 ft/s
Explanation:
a)
The equation of motion of the ball is :
y(t) = -16.1 ft/s^2 * t^2 + Vo*t
Where Vo is the initial velocity
If y(5s) = - 160 ft:
-160 ft = -16.1 ft/s^2 * (5 s)^2 + Vo*(5s)
Solving for Vo
Vo = (16.1*25- 160) ft / 5s = 48.5 ft/s
b)
To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.
v(t) = -32.2 ft/s^2 * t + Vo
t = Vo/32.2ft/s^2 = 1.5 s
And now, the highest point which the ball reached is given by:
y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)
y(1.5s) = 36.52 ft
c)
We now need the time at which y(t') = -64 ft
-64 = -16.1*t'^2 + 48.5*t'
By means of the quadratic formula, we find that
t' = 4.00498 s ≈ 4 s
And the velocity at t = 4s is:
v(4s) = -32.2 ft/s^2 * 4s +48.5 ft/s = -80.3 ft/s
Answer:
D) equal to the flux of electric field through the Gaussian surface B.
Explanation:
Flux through S(A) = Flux through S (B ) = Charge inside/ ∈₀