Read through the solution below. Then, answer

Mathematics

1 answer:

serg [7]1 year ago

6 0

Answer:

the answer is e=mc^2 I think

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Strong moderate or weak correlation r=-0.91, r=0.82, r=-0.49, r=0.26, r=0.54, r=-0.18

Mariulka [41]

So one key thing to remember here is that the direction of the correlation is irrelevant, that is it does not matter if your correlation is + or - what matters is how close that number is to 1.0.

To help you out here are the ranges of correlation strength

0.70. A strong relationship
0.50. A moderate relationship
0.30. A weak relationship

So to start off with 0.26 and 0.18 are very small correlations so you'd call those weak correlations.

Let me know if you need help doing the other ones? It should be simple enough with the data I gave you :)

6 0

2 years ago

Read 2 more answers

Write the equation of the given line in slope-intercept form:<br> (-1,2) and (1,-4)

Oduvanchick [21]

answer is y=-3x+(-1/3)

4 0

2 years ago

Suppose an airline accepted 12 reservations for a commuter plane with 10seats. They know that 7 reservations went to regular com

kvv77 [185]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

7 persons will show up for sure, hence there is not any kind of probability here.

The other 5 persons have 50% chance to show up.

The flight will be overbooked, if either 4 will come or 5 will come.

From the total 5 persons, 4 can be chosen in $^5C_4 = 5$ ways.

The probability that any four among the 5 will come is $5\times(\frac{50}{100} )^{5} = 5\times(\frac{1}{2} )^{5} = \frac{5}{32}$ .

The probability that all of the 5 passengers will come is $\frac{1}{32}$ .

Hence, the required probability is $\frac{5}{32} + \frac{1}{32} = \frac{6}{32} = \frac{3}{16}$ .

(b)

The probability that there will be exactly 10 passengers on the flight is $^5C_3\times (\frac{1}{2} )^5 = \frac{20}{2} \times\frac{1}{32} = \frac{10}{32} = \frac{5}{16}$ .