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Natalija [7]
3 years ago
7

For each expression below, select the letter that corresponds to the equivalent expression given above.

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0
Part 1)
(x²+15x+65)+(2x-5)*(3x+8)
(x²+15x+65)+(6x²+16x-15x-40)
(7x²+16x+25)

the answer Part 1) is the letter B
(7x²+16x+25)

Part 2)
(4x+1)*(3x-4)-(5x²-10x-12)
(4x+1)*(3x-4)-(5x²-10x-12)
(12x²-16x+3x-4)-(5x²-10x-12)
(7x²-3x+8)

the answer Part 2) is the letter D
(7x²-3x+8)

Part 3) 
(8x²+19x+4)+(3x+2)*(x-5)
(8x²+19x+4)+(3x²-15x+2x-10)
(11x²+6x-6)

the answer part 3) is the letter A
(11x²+6x-6)

Part 4) 
(6x+1)*(3x-7)-(7x²-34x-20)
(18x²-42x+3x-7)-(7x²-34x-20)
(11x²-5x+13)

the answer Part 4) is the letter C
(11x²-5x+13)

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wind resistance varies jointly as an objects surface area and velocity. if an object traveling at 55 miles per hour with a surfa
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Answer:

25 miles per hour

Step-by-step explanation:

Given

W = Wind\ resistance

A = Surface\ Area

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The joint variation can be represented as:

W\ \alpha\ A*V

Where:

V = 55; A = 20; W = 220

Required

Find V,  when: A = 55; W = 275

We have:

W\ \alpha\ A*V

Express as an equation

W= k *A*V

Where k is the constant of variation

Make k the subject

k = \frac{W}{A*V}

When: V = 55; A = 20; W = 220

We have:

k = \frac{220}{20 *55 }

k = \frac{220}{1100}

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When: A = 55; W = 275

We have:

k = \frac{W}{A*V}

Substitute: A = 55; W = 275 and k = 0.2

0.2 = \frac{275}{55 * V}

Make V the subject

V= \frac{275}{55 * 0.2}

V= \frac{275}{11}

V= 25

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