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Natalija [7]
4 years ago
7

For each expression below, select the letter that corresponds to the equivalent expression given above.

Mathematics
1 answer:
11111nata11111 [884]4 years ago
3 0
Part 1)
(x²+15x+65)+(2x-5)*(3x+8)
(x²+15x+65)+(6x²+16x-15x-40)
(7x²+16x+25)

the answer Part 1) is the letter B
(7x²+16x+25)

Part 2)
(4x+1)*(3x-4)-(5x²-10x-12)
(4x+1)*(3x-4)-(5x²-10x-12)
(12x²-16x+3x-4)-(5x²-10x-12)
(7x²-3x+8)

the answer Part 2) is the letter D
(7x²-3x+8)

Part 3) 
(8x²+19x+4)+(3x+2)*(x-5)
(8x²+19x+4)+(3x²-15x+2x-10)
(11x²+6x-6)

the answer part 3) is the letter A
(11x²+6x-6)

Part 4) 
(6x+1)*(3x-7)-(7x²-34x-20)
(18x²-42x+3x-7)-(7x²-34x-20)
(11x²-5x+13)

the answer Part 4) is the letter C
(11x²-5x+13)

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\left[\begin{array}{ccc}1&1&\\ \frac{1}{65} & \frac{1}{25} &\end{array}\right]   \left[\begin{array}{ccc}x&\\y&\end{array}\right] =  \left[\begin{array}{ccc}375&\\7&\end{array}\right]

Next, we are going to find the determinant:
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Now that we know the value of x, we can find y:
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Remember that time equals distance over velocity; therefore, the time on the highway will be:
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