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Finger [1]
2 years ago
13

Calculate x and round to nearest tenth​

Mathematics
1 answer:
Pavel [41]2 years ago
3 0
Answer: 10.5

Work:
X=hypotenuse
7=opposite
42=adjacent

Sin42=opp/hyp
Sin42=7/x
0.6691=7/x
0.6691/1 • 7/x
7/0.6691 = 10.461 = 10.5
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How many positive integers can be expressed ad a product of two or more of the prime numbers 5,7,11,and 13 if no one product is
sertanlavr [38]

Answer:

11 positive integers can be expressed.

Step-by-step explanation:

Consider the provided information.

The number of possible prime numbers are 5,7,11,and 13.

There are 4 possible prime numbers.

How many positive integers can be expressed as a product of two or more of the prime numbers, that means there can be product of two numbers, three number or four numbers.

The formula to calculate combinations is: ^nC_r=\frac{n!}{r!(n-r)!}

The number of ways are:

^4C_2+^4C_3+^4C_4=\frac{4!}{2!(4-2)!}+\frac{4!}{3!(4-3)!}+\frac{4!}{4!}

^4C_2+^4C_3+^4C_4=\frac{4!}{2!2!}+\frac{4!}{3!}+1

^4C_2+^4C_3+^4C_4=6+4+1

^4C_2+^4C_3+^4C_4=11

Hence, 11 positive integers can be expressed.

8 0
3 years ago
The following angle measures could form a triangle
qaws [65]

Answer:

They don't form a triangle because all triangles degrees have to add up to 180 if you add them all up its 190 so no they don't form a triangle.

Step-by-step explanation:

84+75+31=190

8 0
3 years ago
Add and Subtract Rational Expressions with a Common Denominator
Sladkaya [172]

Answer:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}

Operating on the numerators:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}

Removing parentheses:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}

Simplifying:

\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}

The expression cannot be further simplified.

7 0
3 years ago
When constructing a prependicular bisector why must the compass opening be greater than 1/2 the length of the segment ?
Tomtit [17]

Because otherwise the two circles you build wouldn't have any intersection!

You have to draw two circles, centered at the endpoints of the segment, and connect their intersection.

If the radii are less than half the length of the circle, the circles will have no interserction.

5 0
3 years ago
The Blazers hockey team has won 7 of its first 12 games.
Step2247 [10]

Answer:

The Rockets' team has the better record.

Step-by-step explanation:

  • The Blazers hockey team has played 12 games but they won only 7 out of the 12 games, so that means that they loss the other 5 games. So that makes the Blazers record 7 wins and 5 losses.

  • The Rockets' team has played 8 games but they won only 5 out of the 8 games, so that means that they loss the other 3 games. So that makes the Rockets' record 5 wins and 3 losses.

  • So, the Rockets' team has the better record because they loss less games than the Blazers team did.
4 0
4 years ago
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