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1 year ago

Please help me!!! I will give brainliest to the correct answer.

Mathematics

2 answers:

lubasha [3.4K]1 year ago

8 0

$\mathsf {2(10 + 2) = 3(y + 3)}$

$\mathsf {24 = 3y + 9}$

$\mathsf {3y = 15}$

$\textsf {y = 5}$

$\textsf {The value of y will be 5. }$

yarga [219]1 year ago

6 0

2(10+2)=3(y+3)
2(12)=3y+9
24=3y+9
3y=15
y=5

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Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon

motikmotik

Given parameters;

Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

Simon has more money than Kande

S > K

if Simon gave Kande K20, they would have the same amount;

if Simon gives $20, his money will be S - 20 lesser;

When Kande receives $20, his money will increase to K + 20

S - 20 = K + 20 ------ (i)

While if Kande gave Simon $22, Simon would then have twice as much as Kande;

if Kande gave Simon $22, his money will be K - 22

Simon's money, S + 22;

S + 22 = 2(K - 22) ------ (ii)

Now we have set up two equations, let us solve;

S - 20 = K + 20 ---- i

S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii

So, S - 20 = K + 20

S + 22 = 2K - 44

subtract both equations;

-20 - 22 = (k -2k) + 64

-42 = -k + 64

k = 106

Using equation i, let us find S;

S - 20 = K + 20

S - 20 = 106 + 20

S = 106 + 20 + 20 = 146

Therefore, Kande has $106 and Simon has $146

3 0

3 years ago

I need help understanding what probability is

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Answer:

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Step-by-step explanation:

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3 years ago

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N+8>11 is the answer you are looking for

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3 years ago

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3 years ago

The length of a rectangle is six times its width. If the area of the rectangle is 384^2, find its perimeter.

Leno4ka [110]

Answer:

Perimeter, P = 112 meters

Step-by-step explanation:

Let the length of the rectangle be L.
Let the width of the rectangle be W.

Translating the word problem into an algebraic expression, we have;

L = 6W ...... equation 1

<u>Given the following data;</u>

Area of rectangle = 384 m²

To find the perimeter of the rectangle;

First of all, we would determine the dimensions of the rectangle using its area.

Mathematically, the area of a rectangle is given by the formula;

Area of rectangle = LW ..... equation 2

Substituting eqn 1 into eqn 2, we have;

384 = 6W(W)

384 = 6W²

Dividing both sides by 6, we have;

W² = 384/6

W² = 64

Taking the square root of both sides, we have;

W = √64

Width, W = 8 meters

Next, we would find the length;

L = 6W

L = 6 * 8

Length, L = 48 meters

Lastly, we would determine the perimeter of the rectangle using the above dimensions;

Mathematically, the perimeter of a rectangle is given by the formula;

Perimeter = 2(L + W)

Substituting the values into the formula, we have;

Perimeter, P = 2(48 + 8)

Perimeter, P = 2(56)

<em>Perimeter, P = 112 meters</em>

4 0

3 years ago