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2 answers:
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Answer:
The answer is below
Step-by-step explanation:
The question is not complete. The complete question is:
The 12 foot long bed of a dump truck loaded with debris must rise an angle of 30 degrees before the debris will spill out. Approximately how high must the front of the bed rise for the debris to spill out.
Solution:
Let x be the height of the front of the bed rise needed to be raised for the debris to spill out. We can find x using trigonometric identities. That is:
sin θ = opposite / hypotenuse
Using trigonometric identities, we can get that:
sin(30) = x / 12
This gives:
0.5 = x / 12
Cross multiplying the terms to get:
x = 12 * 0.5
x = 6 ft
Therefore the front of the bed rise must be raised 6 ft for the debris to spill out.
(a) For dx/dt=6, dy/dt = 2·6 = 12
(b) For dy/dt=2, 2 = 2·dx/dt ⇒ dx/dt = 1
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The value of x is irrelevant for this question.
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If your function is 2^x +1 or 2^(x +1), it needs to be written as such. The answer above applies to the function given.