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1 year ago

What is the mean of, 50, 30, 40, 10, 20, 80, 60, 90, 10, 30, 110, 70?

Mathematics

1 answer:

rjkz [21]1 year ago

4 0

Given:

$50,30,40,10,20,80,60,90,10,30,110,70.$

To find:

The mean

Explanation:

The formula for mean is,

$Mean=\frac{Sum\text{ of the observations}}{Total\text{ number of observations}}$

On substitution we get,

$\begin{gathered} Mean=\frac{50+30+40+10+20+80+60+90+10+30+110+70}{12} \\ =\frac{600}{12} \\ =50 \end{gathered}$

Thus, the mean is 50.

Final answer:

The mean is 50.

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Find the product of (p+5)(p-2)

Korolek [52]

Answer:

The answer is p^2+3p-10

5 0

3 years ago

We have a jar of coins, all pennies and dimes. All together, we have 309 coins, and the total value of all coins in the jar is $

Vinvika [58]

There are 130 pennies in the jar

Step-by-step explanation:

We have a jar of coins

All coins are pennies and dimes
There are 309 coins in the jar
The total value of all coins in the jar is $ 19.2

We need to find the number of pennies in the jar

Assume that there are p pennies and d dimes in the jar

∵ There are p pennies and d dimes in the jar

∵ There are 309 coins in the jar

∵ All the coins in the jar are pennies and dimes

∴ p + d = 309 ⇒ (1)

∵ The total value of all coins in the jar is $ 19.2

∵ $1 = 100 cents

∴ $19.2 = 19.2 × 100 = 1920 cents

∵ 1 penny = 1 cent

∵ 1 dime = 10 cents

∴ p + 10 d = 1920 ⇒ (2)

Now we have system of equations, we can solve them to find p

∵ p + d = 309 ⇒ (1)

∵ p + 10 d = 1920 ⇒ (2)

- Multiply equation (1) by -10 to eliminate d

∵ (-10)(p) + (-10)(d) = (-10)(309)

∴ -10 p - 10 d = -3090 ⇒ (3)

Add equations (2) , (3)

∴ -9 p = -1170

- Divide both sides by -9

∴ p = 130

There are 130 pennies in the jar

Learn more:

You can learn more about the system of equations in brainly.com/question/3739260

#LearnwithBrainly

8 0

3 years ago

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

2 years ago

What is the diameter of 10 inches

wolverine [178]

Answer:

Step-by-step explanation:

C = π x 10cm = 31.42cm (to 2 decimal places).

4 0

2 years ago

PLEASE HELP ME SO I CAN MOVE ON FROM THIS TOPIC

ExtremeBDS [4]

Answer:

3rd option

Step-by-step explanation:

( $\frac{f}{g}$ )(x)

= $\frac{f(x)}{g(x)}$

= $\frac{2x^2-5x-3}{2x^2+5x+2}$ ← factorise numerator and denominator

= $\frac{(x-3)(2x+1)}{(x+2)(2x+1)}$ ← cancel (2x + 1) on numerator/ denominator

= $\frac{x-3}{x+2}$

4 0

2 years ago