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VladimirAG [237]
1 year ago
5

What is the mean of, 50, 30, 40, 10, 20, 80, 60, 90, 10, 30, 110, 70?

Mathematics
1 answer:
rjkz [21]1 year ago
4 0

Given:

50,30,40,10,20,80,60,90,10,30,110,70.

To find:

The mean

Explanation:

The formula for mean is,

Mean=\frac{Sum\text{ of the observations}}{Total\text{ number of observations}}

On substitution we get,

\begin{gathered} Mean=\frac{50+30+40+10+20+80+60+90+10+30+110+70}{12} \\ =\frac{600}{12} \\ =50 \end{gathered}

Thus, the mean is 50.

Final answer:

The mean is 50.

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3 years ago
The feet of the average adult woman are 24.6 cm long, and foot lengths are normally distributed. If 16% of adult women have feet
nevsk [136]

Answer:

Approximately 16% of adult women have feet longer than 27.2 cm.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The feet of the average adult woman are 24.6 cm long

This means that \mu = 24.6

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This means that when X = 22, Z has a p-value of 0.16, so when X = 22, Z = -1. We use this to find \sigma

Z = \frac{X - \mu}{\sigma}

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Approximately what percent of adult women have feet longer than 27.2 cm?

The proportion is 1 subtracted by the p-value of Z when X = 27.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{27.2 - 24.6}{2.6}

Z = 1

Z = 1 has a p-value of 0.84.

1 - 0.84 = 0.16

0.16*100% = 16%.

Approximately 16% of adult women have feet longer than 27.2 cm.

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3 years ago
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