Answer:
JL = 31
Step-by-step explanation:
JL is the total length of the line segment. We know that JK is 15 units long and that KL is 16 units long. So, you would add these numbers (15 & 16) together to get the total length of the line segment. Hope this helps! :)
Answer:

Step-by-step explanation:
The equation of a circle in standard form is

You are given

In order to put the equation in standard from, we need to complete the square. Since there is no y term, the y part is simply y^2, and there is no need to complete the square for y. For x, we do have an x term, so we must complete the square in x.
Start by grouping the x terms and subtracting 45 from both sides.

Now we need to complete the square for x.

The number that completes the square will go in the blank above, and it will also be added to the right side of the equation.
To find the number you need to add to complete the square, take the coefficient of the x term. It is -18. Divide it by 2. You get -9. Now square -9 to get 81. The number that completes the square in x is 81. Now you add it to both sides of the equation.


Answer: 
Answer:
I do not agree with him.
Step-by-step explanation:
even though 20 has no visible decimal digits it has an infinite amount of zeros in the decimal digits. since 1.97 has two digits, then we can just write 20 as 20.00
20.00
- 1.97
_____
18.03
proof:
18.03
+1. 97
______
20.00
Answer:
C) 67.5 to 72.5
Step-by-step explanation:
The value to calculate the confidence interval is given as:

Margin of error is given by:

Using a sample of size n = 3, with 95% confidence the confidence interval came out to be 67 to 73.
We need to identify the new confidence interval if the sample size is increased to n = 16
If you observe the formula, you will see that the sample size(n) is in the denominator. This means, if value of n will be increased the value of fraction will be decreased, which will result in an overall smaller value of margin of error. Since, margin of error is smaller, the values of confidence interval will be closer to the mean.
From here, we can conclude that if sample size is increased, the confidence interval will get narrower. From the given options only option C contains a narrow confidence interval. Therefore, correct answer will be option C: 67.5 to 72.6