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2 years ago

8th grade geometry (triangles), WILL GIVE BRAINLIEST TO THE ONE WHO EXPLAINS HOW THEY CAME TO THE RIGHT ANSWER :))

Mathematics

2 answers:

attashe74 [19]2 years ago

7 0

Answer:

It is either a or d.

Step-by-step explanation:Because even without knowing the lengths, you can tell that b+c is definitely bigger than a, and a+b is definitely bigger than c. So I guess you will just have to take your chances and guess.

Alexus [3.1K]2 years ago

3 0

It is a. A right triangle is proven to be a right triangle with its right angle. Line a and c forms the right angle. C and b are much longer than a, so it is fair to assume that their measurements are a bigger number. It can’t be b, because b + c < a doesn’t make sense as a is the smallest side and b and c are longer. C doesn’t make sense, as side b is longer than c. D doesn’t make sense as the triangle theorem states that the sum of two sides has to be greater than the longest side for it to be a triangle. This is obviously a triangle. So your final answer is a.

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3 years ago

Please help me solve this LCM

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1 year ago

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2 years ago

A ball is projected in to the air. Its height at time t is given by the equation

Ksju [112]

The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:

$h=-16 t^{2} +60t+1$
$8=-16 t^{2} +60t+1$
$16 t^{2} -60t-1+8=0$
$16 t^{2} -60t+7=0$

This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
$t= \frac{-bplus minus \sqrt{ b^{2}-4ac } }{2a}$
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."

In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of) $t^{2}$ = 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7

Substituting these into the quadratic formula gives us:
$t= \frac{-(-60)plus minus \sqrt{ (-60)^{2}-4(16)(7) } }{2(16)}$
$t= \frac{60plus minus \sqrt{3600-448 } }{32}$
$t= \frac{60plus minus \sqrt{3152 } }{32}$

As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
$t= \frac{60+56.1426}{32} =3.63$
and
$t= \frac{60-56.1426}{32} =.12$

So the height is 8 feet at t = 3.63 and t=.12

It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.

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3 years ago