Answer:
is probably y=-2x
Step-by-step explanation:
√<span>108x^5y^6
First, break up </span><span>√108 :
</span>√108 = √4 x √27 = 2 x √3 x √9 = 2 x √3 x 3 = 6<span>√3
</span><span>Since the x^5 is under a root of 2, that means we can take out an x^2 and leave one x under the radical :
</span>√x^5 = x^2 (<span>√x)
</span><span>Since the y^6 is raised to an even power and the root is even (2), that means we can take out all of the y's without leaving any under the radical :
</span><span>√y^6 = y^3
</span><span>Now, combine all of our simplified forms into one expression:
6x^2y^3</span><span>√3x</span><span>
</span>
Wouldn’t it just be 3 units ?
Answer:
V = 6x²(2x - 5)
Step-by-step explanation:
Factor the dimensions, that is
24x² + 6x = 6x(4x + 1) ← common factor of 6x
x² - x = x(x - 1) ← common factor of x
The product lwh can now be written
V =
× (2x - 5) × 
Cancel the factors (4x + 1) and (x - 1) from the numerators/ denominators
V = 6x × x × (2x - 5) = 6x²(2x - 5) ← in factored form