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Harlamova29_29 [7]

1 year ago

7

NoT YellInG ThIS IS JuSt TO AtTRaCT AtTeNTiOn 50 POiNtS PLeaSE ANswER I Am NoT WasTiNg PoInTS!!! Find the range of 1 1/4, 5/8, 3

/4, 1/2, 1 1/2, and 1 3/4

2 answers:

Arada [10]1 year ago

5 0

Answer:

<u>Range = 1 1/4</u>

Step-by-step explanation:

Range = Maximum - Minimum

Arranging the data in ascending order :

<u>1/2, 5/8, 3/4, 1 1/4, 1 1/2, 1 3/4</u>

<u />

Solving for range :

Range = 1 3/4 - 1/2
Range = 1 3/4 - 2/4
Range = 7/4 - 2/4
Range = 5/4
<u>Range = 1 1/4</u>

Crank1 year ago

3 0

Answer: 1 1/4

Exact Form: 5/4
Decimal: 1.25

Explanation: Range is where you subtract the biggest number and the lowest number.

Biggest Number: 1 3/4
Lowest Number: 1/2

1 3/4 - 1/2 = 1 1/4

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Find the values of x and y. Pls helpI’m helpless at math

Svetradugi [14.3K]

Answer:

x = 1

$y=\frac{\sqrt{3}}{2}$

Step-by-step explanation:

From the given right-angle triangle

The angle = ∠60°

The adjacent to the angle ∠60° is 1/2.

The opposite to the angle ∠60° is y.

The hypotenuse = x

<u>Determining the value of x:</u>

Using the trigonometric ratio

cos 60° = adjacent / hypotenuse

substituting adjacent = 1/2 and hypotenuse = x

$cos\:60^{\circ }=\:\:\frac{\frac{1}{2}}{x}$

$\cos \left(60^{\circ \:}\right)=\frac{1}{2x}$

$\frac{1}{2}=\frac{1}{2x}$ ∵ cos (60°) = 1/2

$2x=2$

Dividing both sides by 2

$\frac{2x}{2}=\frac{2}{2}$

Simplify

$x=1$

Thus, the value of hypotenuse x is:

x = 1

<u>Determining the value of y:</u>

Using the trigonometric ratio

sin 60° = opposite / hypotenuse

As we have already determined the value of hypotenuse x = 1

substituting opposite = y and hypotenuse = 1

sin 60° = y/1

y = 1 × sin 60°

$y=\frac{\sqrt{3}}{2}$ ∵ $\sin \left(60^{\circ \:}\right)=\frac{\sqrt{3}}{2}$

Therefore, the value of y is:

$y=\frac{\sqrt{3}}{2}$

Summary:

x = 1

$y=\frac{\sqrt{3}}{2}$

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2 years ago

. If α and β are the roots of

Lostsunrise [7]

Answer:

$18x^2+85x+18 = 0$

Step-by-step explanation:

<u><em>Given Equation is </em></u>

=> $2x^2+7x-9=0$

Comparing it with $ax^2+bx+c = 0$ , we get

=> a = 2, b = 7 and c = -9

So,

Sum of roots = α+β = $-\frac{b}{a}$

α+β = -7/2

Product of roots = αβ = c/a

αβ = -9/2

<em>Now, Finding the equation whose roots are:</em>

α/β ,β/α

Sum of Roots = $\frac{\alpha }{\beta } + \frac{\beta }{\alpha }$

Sum of Roots = $\frac{\alpha^2+\beta^2 }{\alpha \beta }$

Sum of Roots = $\frac{(\alpha+\beta )^2-2\alpha\beta }{\alpha\beta }$

Sum of roots = $(\frac{-7}{2} )^2-2(\frac{-9}{2} ) / \frac{-9}{2}$

Sum of roots = $\frac{49}{4} + 9 /\frac{-9}{2}$

Sum of Roots = $\frac{49+36}{4} / \frac{-9}{2}$

Sum of roots = $\frac{85}{4} * \frac{2}{-9}$

Sum of roots = S = $-\frac{85}{18}$

Product of Roots = $\frac{\alpha }{\beta } \frac{\beta }{\alpha }$

Product of Roots = P = 1

<u><em>The Quadratic Equation is:</em></u>

=> $x^2-Sx+P = 0$

=> $x^2 - (-\frac{85}{18} )x+1 = 0$

=> $x^2 + \frac{85}{18}x + 1 = 0$

=> $18x^2+85x+18 = 0$

This is the required quadratic equation.

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Step-by-step explanation:

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2 years ago

The graph of a line passes through the points (0,-2) and (6,0). what is the equation of the line?

nirvana33 [79]

Answer:

y = 1/3x - 2

Step-by-step explanation:

We are asked to find the equation of a line with two points

Step1: find the slope

m = (y_2 - y_1)/(x_2 - x_1)

( 0 , -2) (6 , 0)

x_1 = 0

y_1 = -2

x_2 = 6

y_2 = 0

Insert the values

m = ( 0 - (-2)/ (6 - 0)

m = ( 0 + 2)/(6 - 0)

m = 2/6

m = (2/2)/(6/2)

m = 1/3

Step 2 : substitute m into the equation of line

y = mx + c

y = intercept y

m = slope

x = intercept x

c = intercept

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Step 3: sub any of the two points

Let's pick ( 6 ,0)

x = 6

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c = 0 - 2

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Sub c = -2

y = 1/3x - 2

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y = 1/3x - 2

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2 years ago

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