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1 year ago

CAN SOMEONE FACTOR THIS PLEASE 125х^6 - 81

Mathematics

1 answer:

alexandr402 [8]1 year ago

3 0

Answer:

Step-by-step explanation:

125×^6_81=0

×^6 we do not support this expression

ans = 0

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I really need on these cause I really don't know this and I need to understand. please help me please.

lawyer [7]

Answer:

-6m^4-m^3

Step-by-step explanation:

First you move the parenthesis then you group the like terms after you group the like terms you get $m^4-7m^4-m^3$ which is adding the similar elements and after you add similar elements you get -6m^4-m^3. Srry if this makes no sense

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2 years ago

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Evaluate the function f(x) at the given numbers (correct to six decimal places).

statuscvo [17]

Answer:

The values of given function are shown in the below table.

Step-by-step explanation:

The given function is

$f(x)=\frac{x^2-5x}{x^2-x-20}$

Simplify the given function.

$f(x)=\frac{x(x-5)}{x^2-5x+4x-20}$

$f(x)=\frac{x(x-5)}{x(x-5)+4(x-5)}$

$f(x)=\frac{x(x-5)}{(x+4)(x-5)}$

Cancel out the common factor.

$f(x)=\frac{x}{x+4}$

Substitute x=5.5 in the above equation.

$f(5.5)=\frac{5.5}{5.5+4}$

$f(5.5)=\frac{5.5}{9.5}$

$f(5.5)=0.57894736842$

$f(5.5)\approx 0.578947$

Similarly find the value for all values of x.

The values of given function are shown in the below table.

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2 years ago

Select all that apply.

lord [1]

Answer:

improved mental health

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3 years ago

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2 years ago

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There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is

shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, $n(P) = 6$

Number of orange socks, $n(O) = 4$

Two socks are picked without replacement.

Now, total number of socks, $n(T)=N(P)+n(O)=6+4=10$

Probability of picking the first cap as purple cap is given as:

$P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}$

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

$P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}$

Now, probability that both the picked caps are purple is given by their probability product. This gives,

$P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33$

Therefore, the probability that he picked 2 purpled socks is 0.33

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2 years ago