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Amiraneli [1.4K]
3 years ago
6

Please help (PLEASE DO NOYPE GIBBERISH FOR POINTS.)

Mathematics
1 answer:
krok68 [10]3 years ago
7 0
It was reduced because as you can see on the scale the actual picture has larger spaces between the numbers.
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How to determine the smallest absolute value
alexandr1967 [171]
The absolute value is basically the distance from zero, and distance is ALWAYS positive. After you removed your negatives, you need to just compare the values. For example. The smallest absolute value between -27 and 19 is 19. Hope this helped!
7 0
3 years ago
Solve the equation using the quadratic formula : x^2-10x+25=18
Sever21 [200]
x^2-10x+25=18 \\ \\x^2-10x+25-18 = 0\\ \\ x^2-10x+ 7 =0 \\ \\a=1 , b = -10 , c= 7 \\ \\ \Delta = b^{2}-4ac = (-10)^{2}-4*1*7=100-28 = 72 \\ \\\sqrt{\Delta }=\sqrt{72}= \sqrt{2*36} =\sqrt{36}*\sqrt{2} =6\sqrt{2}

x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{10- 6\sqrt{2}}{2}=\frac{2(5-3\sqrt{2})}{2}= 5-3\sqrt{2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{10+ 6\sqrt{2}}{2}=\frac{2(5+3\sqrt{2})}{2}= 5+3\sqrt{2}


Answer : \ x= 5-3\sqrt{2} \ \ or \ \ x = 5+3\sqrt{2}


8 0
3 years ago
Problem 1: Given the following probabilities P(Ac) = 0.45, P(B) = 0.34, and P(B|A) = 0.23. Find the following probabilities:
-BARSIC- [3]

Answer:

P(A)=0.55

P(A and B)=P(A∩B)=0.1265

P(A or B)=P(A∪B)=0.7635

P(A|B)=0.3721

Step-by-step explanation:

P(A')=0.45

P(A)=1-0.45=0.55

P(B∩A)=?

P(B|A)=0.23

P(B|A)=(P(A∩B))/P(A)

0.23=(P(A∩B))/0.55

P(A∩B)=0.23×0.55=0.1265

P(A∪B)=P(A)+P(B)-P(A∩B)

=0.55+0.34-0.1265

=0.7635

P(A|B)=[P(A∩B)]/P(B)=0.1265/0.34 ≈0.3721

8 0
3 years ago
On the graph, sketch f(x)=x+3 as well as g(x)=x
tresset_1 [31]

Answer:

below

Step-by-step explanation:

5 0
1 year ago
Someone please help. Giving brainliest!!
padilas [110]

Answer:

A. None of these

Step-by-step explanation:

The largest perfect square under 100 would actually be 81 (9 x 9)

90 and 99 are not perfect squares and 64 is smaller than 81.

8 0
3 years ago
Read 2 more answers
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