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3 years ago

Please help (PLEASE DO NOYPE GIBBERISH FOR POINTS.)

Mathematics

1 answer:

krok68 [10]3 years ago

7 0

It was reduced because as you can see on the scale the actual picture has larger spaces between the numbers.

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Please help 10 point reward

LekaFEV [45]

ANSWER: I can give you the steps to figure out this question.

1 if it is starting at the 6 on the y axis, then just do up 1 over 1 until you get to the 10

The answer to your question is..... 6y+1=4x+10

4 0

3 years ago

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

5 0

3 years ago

Which shape does not have a rotational symmetry?

guapka [62]

Answer:

Trapezoid

Step-by-step explanation: Only a 360 rotation will make the shape appear the same again.

8 0

3 years ago

Read 2 more answers

CAN SOMEONE PLEASE HELP ME???

prohojiy [21]

Answer:

ACF

Step-by-step explanation:

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3 years ago

Sydney read 50 pages in 40 minutes. She reads at a constant rate. How many pages can Sydney read per minute

kodGreya [7K]

Sydney can read 0.8 pages a minute

Solution: you divide the time by the amount of pages read
To confirm 0.8 x 50 = 40

6 0

3 years ago