Question

An unusual number cube (with 6 sides) has the numbers 2, 2, 4, 4, 6, and 6 on its faces.

Answer 1

P(2 or 4) = 2/3

p(multiple of 2) =  1

p(multiple of 3) = 1/3

P(odd prime numbers) = 0

What are the probabilities?

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

P(2 or 4) = (number of sides that have a value of 2 / total number of sides) + (number of sides that have a value of 2 / total number of sides) = 2/6 + 2/6 = 2/3

p(multiple of 2) = number of sides that are a multiple of 2 / total number of sides

6/6 = 1

p(multiple of 3) = number of sides that are a multiple of 3/ total number of sides

= 2/6 = 1/3

P(odd prime numbers) = number of odd prime numbers / total number of sides  = 0

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Answer 2

Answer:

1. P(2 or 4) - 2/3

2. P(multiple of 2) - 1

3. P(multiple of 3) - 1/3

4. P(odd prime numbers) - 0

Step-by-step explanation:

Hope this helps