The answer would be one because .9998 would round the 9 to a 10 which would round the second 9 and then the third nine to make 1
Answer:
3x + 4y = 16 The rule is you can do any valid operation on both sides of an equation and it will still be equal. Subtract 4y.
3x = -4y + 16 Divide by 3.
x = -4y/3 + 16/3 Answer B.
Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
Answer:
See below
Step-by-step explanation:
<u>Parent function:</u>
<u>Transformed function:</u>
- y = 4(3)⁻²ˣ⁺⁸ + 6, (note. I see this as 8, sorry if different but it doesn't make any change to transformation method)
<u>Transformations to be applied:</u>
- f(x) → f(-x) reflection over y-axis
- f(-x) → f(-2x) stretch horizontally by a factor of 2
- f(-2x) → f(-2x + 8) translate 8 units right
- f(-2x + 8) → 4f(-2x + 8) stretch vertically by a factor of 4
- 4f(-2x + 8) → 4f(-2x + 8) + 6 translate 6 units up
