Please help I Don't understand
1 answer:
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6) (b+4)(b+4)
8) (y-3)(y+2)
10) (y-3)(y-5)
12) (b+4)(b+5)
14) (a-3)(a-12)
6) (b+4)(b+4)
8) (y-3)(y+2)
10) (y-3)(y-5)
12) (b+4)(b+5)
14) (a-3)(a-12)
Answer:
the 7th
0.007805 or 59 / 756
Step-by-step explanation:
To determine the Friday that he needed more pounds, determine the number of pounds he needed per dog for each Friday.
to do this, divide the total pounds by the number of dogs
on the 14th
3/8 ÷ 35 =
3/8 x 1/35 = 3/280
on the 7th
1/2 ÷ 27 =
1/2 x 1/27 = 1/54
to determine which fraction is larger multiply each by 100 to determine its percent
3/280 x 100 = 1.071
1/54 x 100 = 1.852
1/54 is larger. Thus, more pounds was needed on Friday the 7th
the difference between these fractions should be determined
-
=
= 59 / 756