Can anyone solve this

WORTH 15 POINTS 15) The Feldmans bought their first house for $20,000. Over the years they moved three times into bigger and big

Law Incorporation [45]

First, find the total inflation over the past 37 years: 37 years * 3.7%/year = 136.9 %. Then just multiply the original cost by the inflation and add the original cost so: ($20,000 * 1.369) + $20,000 = $47,380.

7 0

3 years ago

Please Help! :)<br> You will get brainlyyy

musickatia [10]

Maybe 34.5 !!!!!!!!!!!!!!

7 0

3 years ago

You are studying the water properties of a bog in eastern Wisconsin and wish to estimate its acidity. You de ne a grid that cove

GenaCL600 [577]

Answer:

$4.8-1.453\frac{1.3}{\sqrt{82}}=4.591$

$4.8+1.453\frac{1.3}{\sqrt{82}}=5.009$

So on this case the 85% confidence interval would be given by (4.591;5.009)

And we can conclude that the true mean for the acidity at 85% of confidence is between (4.591;5.009)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=82-1=81$

Since the Confidence is 0.85 or 85%, the value of $\alpha=0.15$ and $\alpha/2 =0.075$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.075,81)".And we see that $t_{\alpha/2}=1.453$