Find the distance from point C to point D.
1 answer:
The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. The distance from point C to point D is 258.8 meters.
<h3>What is Tangent (Tanθ)?</h3>The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. it is given as,
where,
θ is the angle,
Perpendicular is the side of the triangle opposite to the angle θ,
The base is the adjacent smaller side of the angle θ.
The distance from point C to D is equal to the distance from point A to B. Therefore, the height of the building can be written as,
Tan(25°) = AB / BC
Tan(25°) × 555 m = AB
AB = 258.8 meters
Hence, the distance from point C to point D is 258.8 meters.
Learn more about Tangent (Tanθ):
#SPJ1
You might be interested in
Check the picture below.
let's recall that a rhombu's sides are all equal.
<u>ANSWER: </u>
The solution of the two equations 2x+3y=5 and 4x - y=17 is (4, -1).
<u>SOLUTION: </u>
Given, two linear equations are 2x + 3y = 5 → (1) and 4x – y = 17 → (2).
Let us first solve the above equations using <em>elimination process. </em>
For elimination, one of the coefficients of variables has to be same in order to cancel them.
Now solve (1) and (2)
eqn (1) 2 → 4x + 6y = 10
eqn (2) → 4x – y = 17
(-) ----------------------------
0x + 7y = -7
y = -1
Substitute y value in (2)
So, solution of two equations is (4, -1).
<u><em>Now let us solve using substitution process.</em></u>
Then, (2) → 4x – y = 17 → 4x = 17 + y → y = 4x – 17
Now substitute y value in (1) → 2x + 3(4x – 17) = 5 → 2x + 12x – 51 = 5 → 14x = 5 + 51 → 14x = 56
x = 4
Substitute x value in (2) → y = 4(4) – 17 → y = 16 – 17 → y = -1
Hence, the solution of the two equations is (4, -1).