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Dimas [21]
3 years ago
8

A number, x, rounded to 2 significant figures is 1300Write down the error interval for x.​

Mathematics
1 answer:
nikitadnepr [17]3 years ago
7 0

Answer:

[1250,1350).

Step-by-step explanation:

It is given that a number, x, rounded to 2 significant figures is 1300.

It is possible if,

1. The value of x is greater than of equal to 1250 and less than or equal to 1300.

i.e., 1250\leq x\leq 1300     ...(1)

2. The value of x is greater than of equal to 1300 and less than 1350.

i.e., 1300\leq x       ...(2)

On combining (1) and (2), we get

1250\leq x < 1350

1350 is not included in the error interval for x.​

Interval notation is [1250,1350).

Therefore, the error interval for x is [1250,1350).

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Answer:

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8 0
2 years ago
A figure is triangular in shape and is semicircular at the bottom. find perimeter and area of figure
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5 0
3 years ago
Write the equation of the line perpendicular to + = that passes through (−,−). Write your answer in slope-intercept form.
Ad libitum [116K]

Answer:

y = 0.25x - 5

Step-by-step explanation:

Given line is 4x + y = 3

or y = -4x + 3

Comparing this with slope-intercept form y = mx + c :

slope of this line is -4

Product of slopes of perpendicular lines = -1

⇒ slope of a line perpendicular to this is \frac{-1}{-4} = \frac{1}{4} = 0.25

This line also passes through the point (-4,-6)

The equation of a line having slope m and passing through a point (h,k) is

y - k = m(x - h)

⇒ equation of line perpendicular to given line is y - (-6) = 0.25×{x - (-4)}

⇒ y + 6 = 0.25×(x + 4)

⇒ y + 6 = 0.25x + 1

⇒ <u>y = 0.25x - 5</u>

This is in the slope-intercept form y = mx + c with slope m = 0.25 and y-intercept (0,-5)

6 0
4 years ago
Can someone please help me!!!!
Otrada [13]

It is true because if a is perpendicular to b and b is perpendicular to c therefore a has to be perpendicular to c also they said that all three lines are coplanar therefore the statement must be true

I hope this helped you out :)

8 0
3 years ago
A local hamburger shop sold a combined total of 500 hamburgers and cheeseburgers on Wednesday. There were 50 more cheeseburgers
Komok [63]
500-250=250 so if there were 50 more cheeseburgers it would be 300 cheeseburgers so they would of have to sold 200 hamburgers on Wednesday to have sold 500 burgers in total do the answer is 200 hamburgers
4 0
3 years ago
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