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Leni [432]
3 years ago
6

Select 2 options

Mathematics
2 answers:
madreJ [45]3 years ago
8 0

Answer:

(×-5)(×+1)

×^2+×-5×-5

×^2-4×-5

Kobotan [32]3 years ago
5 0

Answer:

the two factors are (x + 1 ) , (x - 5)

Step-by-step explanation:

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Equivalent of (17×4)−35
Thepotemich [5.8K]
17 times 4, you get 68. 68 minus 35, your answer is 33
17*4=68
68-35=33
3 0
3 years ago
If sin(t) = 3/5 and t is in the 2nd quadrant, find cos(t).
NemiM [27]

Cosine is \frac{hypotenuse}{adjacent}.

Apply the equation:

sin(t) = \frac{3}{5} \\3^2 + b^2 = 5^2\\b^2 = 5^2 - 3^2\\\\\sqrt{b^2}  = \sqrt{5^2}- \sqrt{3^2}\\\\\\b = 5 - 3 \\\\b = 2

B is the adjacent side so

cosine is:

Cos(t) = 5/2

Have a great day,

And I hope this helps you!

5 0
2 years ago
A six-foot-tall person is standing next to a flagpole. The person is casting a shadow 1 1/2 feet in length, while the flagpole i
lara31 [8.8K]

Answer: 20 ft

This problem can be solved by the Thales’s theorem, which states:

<em>Two triangles are similar when they have equal angles and proportional sides  </em>

It should be noted that to apply Thales' Theorem, it is necessary to establish <u>the two triangles are similar</u>, that is, that t<u>hey have the corresponding angles equal or that their sides are proportional to each other.  </u>

<u />

Now, if we measure the shadow of the flagpole and the shadow of the person, <u>at the same moment</u>, we can use the first Thales' Theorem to calculate the height of the flagpole, knowing the height of the person.

In this case we have two similar triangles (Figure attached) where H is the height of the flagpole, h=6 ft is the height of the person, A=5 ft is the length of the shadow of the flagpole and a=1\frac{1}{2}=1.5 ft is the length of the shadow of the person.

Having this clear, we can write the following relation with both similar triangles:

\frac{H}{h}=\frac{A}{a}   (1)

We know all these lengths except H, which is the value we want to to find.  

So, in order to approach this problem we have to find H from equation (1):  

H=\frac{A}{a}h  

H=\frac{5 ft}{1.5 ft}(6 ft)  

Then:

H=20 ft >>>>>This is the height of the flagpole

4 0
3 years ago
What is the name of the figure?
Serhud [2]

That is a Triangular Prism.

4 0
3 years ago
Read 2 more answers
Given: ABCD is a trapezoid, AB = CD, BK ⊥ AD, AK = 10, KD = 20 Find: BC AD
alexdok [17]

Answer:

<u> BC = 10 and AD = 30</u>

Step-by-step explanation:

In figure-1 , AB = CD ,BK ⊥ AD,  AK = 10,  KD = 20.

Since, line AD is sum of AK and  KD, then

AD = AK + KD

AD = 10 + 20

AD = 30

Since, BC ║AD and BK ⊥ AD then similarly we construct CL ⊥ AD

so, BC = KL and AK = LD

KL = AD - LD

KL = 20 - 10

KL = 10

Since, BC = KL then BC = 10

Hence, <u> BC = 10 and AD = 30</u>

4 0
3 years ago
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