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1 year ago

Visual domain and range

Mathematics

1 answer:

Mashutka [201]1 year ago

8 0

The domain of a graph of a function is x ∈ [-8, 9] and the range of a graph of a function will be y ∈ [7, 0]

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a graph of a function shown in the picture.

As we can see in the graph there are two bold dots are shown which represents at these points the function value exist.

At x = -8, y = 7

At x = 9, y = 6

At x = -3, y = 0

The domain of a function is x ∈ [-8, 9]

The range of a function is y ∈ [7, 0]

Thus, the domain of a graph of a function is x ∈ [-8, 9] and the range of a graph of a function will be y ∈ [7, 0]

Learn more about the function here:

brainly.com/question/5245372

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3 years ago

Read 2 more answers

How to do the problem

marta [7]

There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
$8 \frac{1}{4} + 9 \frac{1}{4} + 8 \frac{7}{8} + 9 \frac{5}{8} + 10 \frac{3}{4}$
$= \frac{8 \times 4 + 1}{4} + \frac{9 \times 4 + 1}{4} \\ + \frac{8 \times 8 + 7}{8} + \frac{9 \times 8 + 5}{8} \\ + \frac{10 \times 4 + 3}{4}$
$= \frac{33}{4} + \frac{37}{4} + \frac{71}{8} + \frac{77}{8} + \frac{43}{4} \\ = \frac{33 \times 2}{4 \times 2} + \frac{37 \times 2}{4 \times 2} + \frac{71}{8} \\ + \frac{77}{8} + \frac{43 \times 2}{4 \times 2}$
$= \frac{66 + 74 + 71 + 77 + 86}{8}$
$= \frac{374}{8} = \frac{186}{4}$
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
$\frac{186 - 153}{4} = \frac{33}{4} = 8 \frac{1}{4}$

The leftover watermelon is 8 & 1/4 pounds.

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2 years ago

Find all unit vectors that are orthogonal to the vector u = 1, 0, −4 .

KIM [24]

Answer:

Step-by-step explanation:

Given:

u = 1, 0, -4

In unit vector notation,

u = i + 0j - 4k

Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.

If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then

u. v = 0 [<em>substitute for the values of u and v</em>]

=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k) = 0 [<em>simplify</em>]

=> v₁ + 0 - 4v₃ = 0

=> v₁ = 4v₃

Plug in the value of v₁ = 4v₃ into vector v as follows

v = 4v₃ i + v₂ j + v₃ k -------------(i)

Equation (i) is the generalized form of all vectors that will be orthogonal to vector u

Now,

Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

$\frac{v}{|v|}$

Where;

|v| = $\sqrt{(4v_3)^2 + (v_2)^2 + (v_3)^2}$

|v| = $\sqrt{17(v_3)^2 + (v_2)^2}$

$\frac{v}{|v|}$ = $\frac{4v_3i + v_2j + v_3k}{\sqrt{17(v_3)^2 + (v_2)^2}}$

This is the general form of all unit vectors that are orthogonal to vector u

where v₂ and v₃ are non-zero arbitrary real numbers.

3 0

3 years ago