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Alika [10]
3 years ago
6

In a bag, there are six white balls and four black balls. I take out two balls at random, one at a time, without replacement. Wh

at is the probability that the second ball I take is black
Mathematics
1 answer:
Sphinxa [80]3 years ago
7 0

Answer:

Probability = 0.4

Step-by-step explanation:

Given

White = 6

Black = 4

Required

Probability that second is black

This selection can be represented as:

(Black and Black) or (White and Black)

The probability of Black and Black is:

P(Black\ Only) = \frac{Black}{Total} * \frac{Black - 1}{Total - 1}

<em>1 is subtracted from the second fraction because it is probability without replacement</em>

P(Black\ Only) = \frac{4}{10} * \frac{4- 1}{10 - 1}

P(Black\ Only) = \frac{4}{10} * \frac{3}{9}

P(Black\ Only) = \frac{2}{5} * \frac{1}{3}

P(Black\ Only) = \frac{2}{15}

The probability of White and Black is:

P(Black\ and\ White) = \frac{Black}{Total} * \frac{White}{Total - 1}

<em />

<em>1 is subtracted from the second fraction because it is probability without replacement</em>

P(Black\ and\ White) = \frac{4}{10} * \frac{6}{10- 1}

P(Black\ and\ White) = \frac{4}{10} * \frac{6}{9}

P(Black\ and\ White) = \frac{2}{5} * \frac{2}{3}

P(Black\ and\ White) = \frac{4}{15}

So, the required probability is:

Probability = P(Black\ Only) + P(Black\ and\ White)

Probability = \frac{2}{15} + \frac{4}{15}

Probability = \frac{2+4}{15}

Probability = \frac{6}{15}

Probability = 0.4

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