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Andrei [34K]
2 years ago
5

Find the exact length of the curve. x = 5 + 9t2, y = 4 + 6t3, 0 ≤ t ≤ 3

Mathematics
1 answer:
kodGreya [7K]2 years ago
3 0

The exact length of the curve given the following system of inequalities is ≈ 1637.

<h3>What is a system of inequalities?</h3>

A system of inequalities refers to a set of two or more inequalities with one or more variables. This kind of system is used when a problem needs a range of solutions a there is over one constraint.

<h3>What is the length of the curve with the above system of inequalities?</h3>

Step One - Let's restate the equations

We have:

x = 5 + 9t²

y = 4 + 6t³

Where

0 ≤ t ≤ 3

Step 2 - Differentiate them

The first derivative of dx/dt

= d/dt [9t² + 5)

= 9 * (d/dt) (t²) + (d/dt) (5)

= 9.2t + 0

= 18t

Also differentiate (dy/dt)

= d/dt [6t² + 4]

= 6 * (d/dt) [t³] + (d/dt) [4]

= 6.3 t² + 0

= 18t²

To find the length of the arc:

L = \[ \int_{0}^{4} \sqrt{(\frac{dx}{dt})^{2}  + (\frac{dy}{dt})^{2}  dt }

We can thus deduce that:

= \[ \int_{0}^{4} \sqrt{(\fra18t)^{2}  + ({18t^{2} )^{2} dt }

= \int_{0}^{4}[18t \sqrt{1 + {18t^{2} ]

Compute the definite integral and factor out the constraints and we have:

dt = 4912/3

≈ 1,637.3

Hence the exact length of the curve is

≈ 1637

Learn more about the system of inequalities at:
brainly.com/question/9774970
#SPJ1

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Answer:

a) P(A) = 0,4607     or   P(A) = 46,07 %

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c) P(C) = 0,2055  or P(C) = 20,55 %

Step-by-step explanation:

We will use two concepts in solving this problem.

1.- The probability of an event (A) is for definition:

P(A) = Number of favorable events/ Total number of events FE/TE

2.- If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

a) The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )!    ⇒  C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!  

C ( 24,4) = 24*23*22*21/4*3*2

C ( 24,4) = 24*23*22*21/4*3*2    ⇒  C ( 24,4) =  10626

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we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3)  = 6 * 18! / 3!*15!  =  18*17*16*15!/15!

FE =  4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) will be the probability of at least 1 tank contains h-v

P(B) = 1 - P ( no one tank with h-v)

Again Total number of events is 10626

The total number of favorable events for the ocurrence of P is C (18,4)

FE = C (18,4) = 18! / 14!*4! = 18*17*16*15*14!/14!*4!

FE = 18*17*16*15/4*3*2  = 3060

Then P = 3060/10626

P = 0,2879

And the probability we are looking for is

P(B) = 1 - 0,2879

P(B) = 0,7120   or 71,2 %

c) We call P(C) the probability of finding exactly 1 tank with h-v and t-i

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reasoning the same way but now having 4 with t-i (impurities) number of favorable events is:

FE = 6*4* C(14,2) = 24 * 14!/12!*2!

FE = 24* 14*13*12! / 12!*2

FE = 24*14*13/2    ⇒  FE = 2184

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