<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
Answer: 0.27
Step-by-step explanation:
Move the decimal two places to the left
Answer:
En la última fila de la zona general hay 98 asientos y en la zona preferencial hay 564 asientos.
Explicación paso a paso:
= 1 + − 1 ×
40 = 20 + 40 − 1 × 2
40 = 20 + 39 × 2
40 = 20 + 78
40 = 98
= (1 + ) 2 ×
12= (36 + 58) 2 ×12
12 = 47 × 12
12 = 564
Step-by-step explanation:
dame corona
Answer:
Step-by-step explanation:
It's already in a form that only ha positive exponents. Just to state it though you could rewrite it as 
or 
The question asks for positive exponents though so yu don't need to do that.
You also need to know 
so in this case 
so 
