Answer: The outbound trip is 18 miles per hour
Step-by-step explanation:
Let x represent the speed of the plane.
An aircraft carrier made a trip. Let us assume that this trip was outbound. The trip there took 5 hours.
Distance = speed × time. Therefore
Distance = 5x
The trip back took 6 hours. It averaged 3 mph faster on the trip there then on the return trip. This means that the speed on the trip back is x - 3 mph.
Distance = 6(x-3) = 6x - 18
Since the distance is the same,
5x = 6x - 18
6x - 5x = 18
x = 18
The speed on return or inbound trip would be 18 - 3 = 15 mph
Answer:
y= -2x
Step-by-step explanation:
To find the slope, convert the standard form of the equation into slope intercept form, y=mx+b.
5x-10y=-12
-10y=-5x-12
y=1/2 x + 1.2
The slope is 1/2 and the slope of the new line will be -2 because the negative reciprocal create a perpendicular line. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.
(y-8)=-2(x--4)
y-8=-2(x+4)
y-8=-2x -8
y= -2x +0
Answer:
-3
Step-by-step explanation:
Let, the time when <span>Jan cough up to Carol = x
We know, Distance = Speed * Time.
So, Equation would be: 2x + 5*2 = 6x
2x + 10 = 6x
6x - 2x = 10
4x = 10
x = 10/4 = 2.5
Distance traveled in that time = 2.5 * 6 = 15 miles
In short, Your Answer would be: 15 miles
Hope this helps!</span>
It will take jen 20 weeks till she can get a new camping tent