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vivado [14]
1 year ago
11

5,3 = 287,6 = 554,5 = 213,8 = ?​

Mathematics
1 answer:
Bond [772]1 year ago
5 0

Answer:

17

Step-by-step explanation:

3×3+8

i applied BODMASS RULE

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What is the conjugate? See image below! Please help asap
Stolb23 [73]

9514 1404 393

Answer:

  • 2 +3i
  • 8 -i√5
  • 7 +2i
  • 4 +√7

Step-by-step explanation:

The conjugate is found by changing the sign of the square root term.‡ (For this purpose, i = √-1.)

a) the sign of 3i is changed: 2 + 3i

b) the sign of sqrt(-5) is changed: 8 -sqrt(-5) = 8 -i√5

c) the sign of 2i is changed: 7 +2i

d) the sign of sqrt(7) is changed: 4 +√7

_____

‡ Actually, the conjugate of a binomial is formed by changing the sign <em>between</em> terms. The purpose is to allow the product of the binomial and its conjugate to be the difference of squares.

Conventionally, the conjugate of a complex number is the value with the sign of the imaginary part reversed. That is why (-2i+7)* = 7+2i.

4 0
2 years ago
Rewrite with only sin x and cos x.
Annette [7]

Option A

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

cos 3x = cos(x + 2x)

We know that,

\cos (a+b)=\cos a \cos b-\sin a \sin b

Therefore,

\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x  ---- eqn 1

We know that,

\sin 2 x=2 \sin x \cos x

\cos 2 x=\cos ^{2} x-\sin ^{2} x

Substituting these values in eqn 1

\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)  -------- eqn 2

We know that,

\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x

Applying this in above eqn 2, we get

\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)

\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}

\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x

Therefore,

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

Option A is correct

7 0
2 years ago
X - x-2/6 = x-7/3 + 2/3
elena-s [515]
X-x-2/6=x-7/3+2/3
-2/6+7/3-2/3=x
x= -2/6+5/3
x= 8/6
x= 4/3
3 0
2 years ago
HELP PLEASEEE!!!! I START SCHOOL TOMORROW
ohaa [14]

Answer:

4. The range is -2 ≤ y ≤ 4

5. The domain is {-2 , -1 , 0 , 3.5 , 4.2}

6. The relation is not a function

Step-by-step explanation:

* Lets explain how to solve the problem

# Question 4:

- The range of the function is the values of all y (output) which is

 corresponding to the values of all x (input)

- The figure is a stare, the values of x is from -4 to 4

∴ The domain is -4 ≤ x ≤ 4

- The corresponding values of y are from -2 to 4

∴The range is -2 ≤ y ≤ 4

# Question 5:

- The table represent a relation between x and y

- x is the input of the relation

- y is the output of the relation

∵ The input of the relation is called the domain of it

∴ The domain of the relation is all values of x in the table

- the values of x are -2 , -1 , 0 , 3.5 , 4.2

∴ The domain is {-2 , -1 , 0 , 3.5 , 4.2}

# Question 6:

- The relation can be a function if each ordered pair has a

  unique value of x (input)

- That means every x (input) has only one y (output)

- Ex : The relation {(a , b) , (c , d) , (a , f)} is not a function because

 the input a has two output b and f

∵ The relation is {(-4 , 0) , (-3 , 0) , (-2 , 1) , (1 , -2) , (-3 , 4)}

∵ The x = -3 has two values of y 0 and 4

∴ The relation is not a function

7 0
3 years ago
Please help brainiest is award.
Thepotemich [5.8K]

Answer:

*reward

Step-by-step explanation:

i has helped your welcome

7 0
3 years ago
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