If f(x) = x, then f(64) is equal to<br><br> a. 1/4<br> b. -8<br> c. -4<br> d. 4

Solve for x on the interval 0≤x<2pi<br><br> cos(3x)=1/2

Ede4ka [16]

We will see that the solution in the given interval is: x = 0.349 radians.

<h3>How to solve equations with the variable in the argument of a cosine?</h3>

We want to solve:

cos(3*x) = 1/2

Here we must use the inverse cosine function, Acos(x). Remember that:

cos(Acos(x)) = Acos(cos(x)) = x.

If we apply that in both sides, we get:

Acos( cos(3x) ) = Acos(1/2)

3*x = Acos(1/2)

x = Acos(1/2)/3 = 0.349

So x is equal to 0.349 radians, which belongs to the given interval.

If you want to learn more about trigonometry, you can read:

brainly.com/question/8120556

7 0

2 years ago

4/5 equivalent fraction?

Grace [21]

4/5 = 8/10 = 12/15 = 16/20 = 20/25
Hope it helps

6 0

3 years ago

For every $12 he earns babysitting , he saves $5 , on saturday , rob earned $48 babysitting how much money did he save

laila [671]

He saved $20

Hope this helps

5 0

4 years ago

Read 2 more answers

How is the series 5+11+17…+251 represented in summation notation?

NISA [10]

Answer:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

Step-by-step explanation:

Given:

Series 5+11+17+...+251

To find:

Summation notation of the given series

Summation Notation:

$\displaystyle \large{\sum_{k=1}^n a_k}$

Where n is the number of terms and $\displaystyle \large{a_k}$ is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

Arithmetic Series

A series that has common difference.

Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

11-5 = 6
17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

$\displaystyle \large{a_n=a_1+(n-1)d}$

Where $\displaystyle \large{a_n}$ is the nth term, $\displaystyle \large{a_1}$ is the first term and $\displaystyle \large{d}$ is the common difference:

So for our general term:

$\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}$

And for number of terms, substitute $\displaystyle \large{a_n}$ = 251 and solve for n:

$\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}$

Now we can convert the series to summation notation as given the formula above, substitute as we get:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

5 0

2 years ago

Write 5+4 in doubles

allsm [11]

I think its 5 + 5 or 4+4

6 0

3 years ago

If f(x) = x, then f(64) is equal to a. 1/4 b. -8 c. -4 d. 4