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Tanzania [10]
3 years ago
14

Suppose y varies directly with x. If y=-20 when x=2, find y when x=14

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
8 0
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=-20\\
x=2
\end{cases}\implies -20=k2\implies \cfrac{-20}{2}=k
\\\\\\
-10=k\qquad therefore\qquad \boxed{y=-10x}
\\\\\\
\textit{when x = 14, what is \underline{y}?}\qquad y=-10(14)
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Answer:

Step-by-step explanation:

1.

(-2,0) (0,-7)                y2-y1

                            -----------------

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-7-0= -7

0- (-2)= 2             ------>>> -7/2 =m or slope

2.

y= -7/2x+b          to find b u plug in one pair of coordinates for example (-2,0)

                          and use inverse properties to find b

0 = -7/2(-2) + b

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0= 7+b

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y=-7/2x-7    

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anyanavicka [17]

Step-by-step explanation:

about circle R

arc angle MP = angle MRP = 78°

angle M = angle LMP.

according to the rules of inscribed angles, LMP is half of angle LRP.

LRP + MRP = 180° because together they cover the whole LM segment (half-circle).

LRP = 180 - MRP = 180 - 78 = 102°

so, LMP = angle M = 102/2 = 61°

also circle R (with arc ULNP)

the arc ULNP = arc UL + arc LN + arc NP = 160°

due to the congruent definition of JU and MP we know that arc UL = arc NP.

and we know arc LN = arc JM = 18°.

so,

160 = 2×arc NP + 18

142 = 2×arc NP

arc NP = 71° = arc UL

now, because arc MP + arc LP = 180 (half-circle),

arc MP = 180 - arc LP = 180 - arc LN - arc NP =

= 180 - 18 - 71 = 91°

about the circle R with 2 congruent chords :

the second answer : they are equidistant from R (the center of the circle).

about circle W

arc MK + arc KL = 180° (half-circle).

and we see

arc HL = arc KL = 53°.

so,

arc MK + 53 = 180°

arc MK = 180 - 53 = 127°

about circle M

arc QTS = 204°.

therefore, arc QRS = 360 - arc QTS = 360 - 204 =

= 156° = angle QMS.

according to the rules of inscribed angles

angle QTS = QMS/2 = 156/2 = 78°

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