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3 years ago

8 5/6 + 2 3/4 +__=14 this is fractions so the answer should be a fraction please help

Mathematics

1 answer:

Mariulka [41]3 years ago

3 0

Answer:

2 5/12

Step-by-step explanation:

8 5/6 + 2 3/4 = 8 10/12 + 2 9/12 = 10 19/12 = 10 + 1 7/12 = 11 7/12

13 12/12 - 11 7/12 = 2 5/12

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1. Order the numbers from least to greatest. 66 V21, 5.38 3

IrinaK [193]

Answer:

3, 5.38, 66, V21

Step-by-step explanation:

I assumed that V was the roman numeral V, which is equivalent to the number 5. I then multiplied 5 by 21 which is 105. If this is not the case and they simply wanted us to replace the v with a 5, then the answer would still be correct because 521 is greater than all the numbers in this set. Hope this helps.

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3 years ago

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3 years ago

What is the common ratio of 2, 10/3, 50/9

mojhsa [17]

The common ratio of 2, 10/3, 50/9 is $\frac{10}{6}$

<u>Solution:</u>

Given, series of elements are $2, \frac{10}{3}, \frac{50}{9}$

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take $\frac{10}{3}$ and 2

$\text { Then, common ratio }=\frac{\frac{10}{3}}{2}$

$\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}$

Hence, the common ratio of the given series is $\frac{10}{6}$

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3 years ago

Marine fuel is a combination of gasoline and motor oil. The standard gasoline and oil mixture is about 98% gasoline and about 2%

Georgia [21]

Answer:

0.98g+ 0.02m= 7.1224 gallons standard mixture

0.96g+ 0.04m= 6.25 gallons break oil

3.92 gallons of gasoline is required for 4 gallons the standard mixture

Step-by-step explanation:

If we have to use 6 gallons of gasoline this means that 98%= 6 gallons and 2% would be 6/98*2

Gasoline: Motor oil

6 : x

98 : 2

Using the product rule

x= 6*2/98= 0.1224 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the standard oil the equation would be

0.98g+ 0.02m= 7.1224 gallons standard mixture

For break in oil

Gasoline: Motor oil

6 : x

96 : 4

Using the product rule

x= 6*4/96= 0.25 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the break oil the equation would be

0.96g+ 0.04m= 6.25 gallons break oil

Part b. For 4 gallons of the "break in" mixture

96% of the 4 gallons of the "break in" mixture is gasoline = 3.84 gallons of gasoline

4% of 4 = 0.16 gallons of motor oil

Now the standard mixture 4 gallons would contain 98 % of gasoline and 2 % of motor oil

98% of 4 gallons= 3.92 gallons of gasoline

2% of 4 gallons= 0.08 gallons of motor oil.

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3 years ago

Workout the value of x.

anyanavicka [17]

Answer: The value of X is 97 degrees

Explanation:

7 0

2 years ago