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Ludmilka [50]
3 years ago
12

Lily sold 18 items at the street fair. she sold bracelets for $6 each and necklaces for $5 each for a total of $101. which syste

m of equations can be used to find b, the number of bracelets she sold, and n, the number of necklaces she sold? b n = 101 6b 5n = 18 b n = 101 5b 6n = 18 b n = 18 6b 5n = 101 b n = 18 5b 6n = 101
Mathematics
1 answer:
katrin [286]3 years ago
4 0

Answer:

b + n = 18

6b + 5n = 101

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inessss [21]

Step-by-step explanation:

is it like this ? no diagrams ?

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Step 2 a negative times a positive is a negative so the answer is -75.6
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The ratio of boys to girls in a
dybincka [34]

Answer:

48+x/x=7/1

48+x=7x

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an organic farm uses 3/7 of the land to grow potatoes and two fifths of the land to grow spinach the remaining land is used to g
melomori [17]
<span>The organic farm uses 3/7 of the land to grow potatoes
=> 2 /5 of the land to grow spinach
=> x = the fraction of the land to grow tomato plants.
The easiest wat to get the answer is convert first the fraction to decimals
=> 3/7 = 0.43
=> 2/5 = 0.4
=> x = ???
=> 0.43 + 0.4 = 0.83
=> let the whole land = 1
=> 1 – 0.83
=> 0.17, the remaining land left for tomato plants
Convert now to fraction
=> 17/100</span> (Approximately)

YOu can also use this method:
=> 3/7+ 2/5 +x = ?
Find the LCM
=> 3/7 + 2/5 = 29/ 35
=> 35/35 - 29 / 35
=> 6 / 35, the remaining land




8 0
4 years ago
Find the slope of each line.
Amiraneli [1.4K]

to get the slope of a line all we need is two points off of it, so let's get two points from that table

\bf ~\hspace{4em}\downarrow ~\hspace{1.5em}\downarrow \\ \begin{array}{|ccccc|} \cline{1-5} x&0&1&2&3\\ \cline{1-5} y&-\frac{1}{3}&\frac{1}{3}&1&\frac{5}{3} \\ \cline{1-5} \end{array}\qquad \qquad (\stackrel{x_1}{1}~,~\stackrel{y_1}{\frac{1}{3}})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{\frac{5}{3}})

\bf \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{\frac{5}{3}}-\stackrel{y1}{\frac{1}{3}}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{1}}}\implies \cfrac{~~\frac{4}{3}~~}{2}\implies \cfrac{~~\frac{4}{3}~~}{\frac{2}{1}}\implies \cfrac{\stackrel{2}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{3}\cdot \cfrac{1}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \cfrac{2}{3}

6 0
3 years ago
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