Check the picture below.
since in a rhombus the diagonals bisect each other, thus EC = EA.
now, the rhombus is simply 4 congruent triangles, we know the base and height of one of them, thus
![\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=8\\ h=15 \end{cases}\implies A=\cfrac{1}{2}(8)(15)\implies A=60 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of all 4 triangles}}{4(60)\implies 240}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20triangle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dbh~~%20%5Cbegin%7Bcases%7D%20b%3D8%5C%5C%20h%3D15%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%288%29%2815%29%5Cimplies%20A%3D60%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20all%204%20triangles%7D%7D%7B4%2860%29%5Cimplies%20240%7D)
Answer:
(x,y) = (-1,1)
Step-by-step explanation:
Given the equations
y = 2x + 3
x - y = -2
substitute the value of y in the first equation into the second
x - (2x + 3) = -2
x -2x - 3 = -2
-x - 3 = -2
add 3 to both sides
-x = -2 + 3
- x = 1
Divide both sides by -1
x = -1
Substitute into the first equation
y = 2(-1) + 3
y = -2 + 3
y = 1
Answer:
7x - 3)
Step-by-step explanation:
Given
3x - 7 + 2(2x - 7) ← distribute parenthesis
= 3x - 7 + 4x - 14 ← collect like terms
= 7x - 21 ← factor out 7 from each term
= 7(x - 3)
Answer:
-6p^5+48p
Step-by-step explanation:
-6p (p^4- 8)= -6p^5+48p
Answer:
4x² - x - 1
Step-by-step explanation:
(f - g)(x) = f(x) - g(x) , thus
f(x) - g(x)
= 4x² - (x + 1) ← distribute parenthesis by - 1
= 4x² - x - 1
