The answer to your question would be 'A'
Answer:
D is the right answer
Step-by-step explanation:
Answer:
$9$
Step-by-step explanation:
Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.
To find: number that Thea originally entered
Solution:
The final number is $243$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $243$ must be $324$.
As previously the number was squared, so the number before $324$ must be $18$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $18$ must be $81$
As previously the number was squared, so the number before $81$ must be $9$.
10
sum is add
cube is to the 3rd powr
19+x³
11.
product means multiply
3 times y is no more than (equal to or less than ) 21
3y≤21
no need to solve
12. 2 times difference is 10
difference is subtract
2(z-12)=10
Ratio is 6:5
6+5=11
Men: 6 parts of 11 = 3600
6=3600
1=x
X=3600/6
=600.
Women: 5 parts of 11
1 part = 600
5 parts = 600x5
=3000
