Question

Determine the slope-intercept form of the equation of the line parallel to y = x + 11 that passes through the point (–6, 2). y = x +

Answer 1

Answer:

$y = x+12$

Step-by-step explanation:

Parallel => This means it has the same slope as this one.

Slope = m = 1

Now,

Point = (x,y) = (-6,2)

So, x = -6, y = 2

Putting this in slope intercept form to get b

$y = mx+b$

=> 2 = (1)(-6) + b

=> b = 2+6

=> b = 8

Now putting m and b in the slope-intercept form to get the required equation:

=> $y = mx+b$

=> $y = x+12$