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zmey [24]
2 years ago
9

Carl is making a garden that is twice as long as it is wide. he wants to cover 271

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
6 0

x²/2 =271 represents the situation where taking length twice as breadth and area as 271 ft² .

Area of a figure is the amount of space acquired by the figure

Area of a rectangle=Length x  breadth

length=x

breadth=x/2

Area of rectangular lawn=lxb

                                          =x.x/2

But as per question,

Area=271 ft²

⇒x²/2=271 1

⇒x=23.28 ft²

Therefore, x²/2 =271 represents the situation where taking length twice as breadth and area as 271 ft² .Value of x i.e. length is 23.28 ft²

Learn more about area,

brainly.com/question/25292087

#SPJ10

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GalinKa [24]

Answer:

i did the first

Step-by-step explanation:

1st way

Standard form: a(X-h)²+k = ( -2/3X² -16/3X -32/3) +32/3 -17/3 = -2/3(X +4)² +5

y = -2/3*X^2-16/3*X-17/3

X = -4 ±√( 15/2) = -6.7386, or -1.2614

Axis of symmetry: X= -4; Vertex (maximum)=(h,k)=( -4, 5); y-intercept is (0,-5.66666666667)

two real roots: X=-1.2613872124776866 and -6.738612787477313

5 0
3 years ago
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5(m+4)=-2(-4-m)+3<br> help please
Degger [83]

Answer:

m = -3

Step-by-step explanation:

5m + 20 = 8 + 2m +3

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3 years ago
How many photons with 10 ev are required to produce 20 joules of energy?
alexira [117]
1 joule = 6,242e+18ev

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SpyIntel [72]
The correct answer is -2
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3 years ago
The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of
kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

A=\frac{\sqrt{3} }{4} a^{2}

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}

A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}

A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}

Now, comparing areas:

\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )

\frac{A_{1}}{A_{2}} = 2.25

<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

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3 years ago
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