144.44 in² is the closest amount of paper she will use to wrap the gift.
Solution:
The given net is the shape of the cylinder.
Diameter of the circle = 4 in
Radius of the circle = 4 ÷ 2 = 2 in
Width of the container = 10.5 in
Length of the container is same as the circumference of the circle.
Area of the circle = 
= 
= 12.56 in²
Area of the 2 circles = 2 × 12.56 = 25.12 in²
Area of the rectangle = circumference × height
= 
= 
= 131.88 in²
Area of the net of the container
= Area of the circles + Area of the rectangle
= 12.56 in² + 131.88 in²
= 144.44 in²
Area of the net of the container = 144.44 in²
Hence 144.44 in² is the closest amount of paper she will use to wrap the gift.
Answer:
Step-by-step explanation:
3/4
The answer to your question is $30
Step-by-step explanation:
A:
No graph has been shown.
B:
<u>1.</u>
d = 2.5(20)
d = 50 meters.
<u>2.</u>
time distance H distance E
0 45 0
5 50 12.5
15 60 37.5
20 65 50
40 85 100
65 - 50 = 15
15 meters
Look at graph image for the distance represented on the graph.
Answer:
B. TRUE.
(3, 2) is the intersection point of the graphs of
x + y = 5 and x - y = 1.
Step-by-step explanation:
Option B is TRUE because intersection point should satisfy both the equation
and in option be it comes true.
i.e x = 3 and y = 2 we have
3 + 2 = 5 and 3 - 2 = 1
5 = 5 and 1 = 1
Hence TRUE
A.
(3, 2) is the intersection point of the graphs of
3x + 2y = 5 and 3x - 2y = 1.
i.e x = 3 and y = 2 we have
3×3 + 2×2 = 5 and 3×3 - 2×2 = 1
13 ≠ 5 and 5 ≠ 1
Hence FALSE
C.
(5, 1) is the intersection point of the graphs of
3x + 2y = 5 and 3x - 2y = 1.
i.e x = 5 and y = 1 we have
3×5 + 2×3 = 5 and 3×5 - 2×3 = 1
21 ≠ 5 and 9 ≠ 1
Hence FALSE
D.
(5, 1) is the intersection point of the graphs of
x + y = 5 and x - y = 1.
i.e x = 5 and y = 1 we have
5 + 1 = 5 and 5 - 1 = 1
6 ≠ 5 and 4 ≠ 1
Hence FALSE
