its -5 so it is A,( -19/2, -5)
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
9514 1404 393
Answer:
Step-by-step explanation:
If we let x and y represent the costs of a lamp and end table, respectively, the two purchases can be written as ...
3x +2y = 520
2x -y = 20
__
These equations can be solved many ways. If we use "elimination", we can add twice the second equation to the first to eliminate y:
(3x +2y) +2(2x -y) = (520) +2(20)
7x = 560 . . . . simplify
x = 80 . . . . . . divide by 7
y = 2x -20 = 2(80) -20 = 140
The cost of a lamp is $80; the cost of an end table is $140.
Answer:
D-y=-3x+5
Step-by-step explanation:
Slope is -3x and y intercept is positive 5
Answer:
B. 3x3+6x−2
Step-by-step explanation:
When you divide 3x3+6x−2 by x+1 we get a remainder of -11.
