which choice could be the equation of a line perpendicular to the line represented by this equation? y=2/5x=2 answers choice A(
1 answer:
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X-y=5
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula
for
ay^2+by+c=0
for 1y^2+5y-3.36
y=-2.5+/-3.1
y=5.6 or 0.6
sub back
x=y+5
so
x=10.6 or 5.6
the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer
answer is 0.6 and 5.6
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula
for
ay^2+by+c=0
for 1y^2+5y-3.36
y=-2.5+/-3.1
y=5.6 or 0.6
sub back
x=y+5
so
x=10.6 or 5.6
the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer
answer is 0.6 and 5.6
Answer:
The answer is the option D
the minimum number of students will be
Step-by-step explanation:
Let
x-------> the minimum number of students
we know that
------> inequality that represent the situation
The domain of the inequality is the interval------->
Solve for x
Divide by both sides
so
the minimum number of students will be