The two squares x and y are mathematically similar. The areas of x and y are 17cm squared and 272cm squared, respectively. The l
1 answer:
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<span>Part 1:
option b.
Part 2:
option d
Part 3:
Multiply through by the LCM of 2 and 3 (i.e. 6)
option b
Part 4
x^2-3x-8=x+4
option d
Part 5
Joseph is solving the equation x^2+8x-4=0 using the technique completing the square.
x^2+8x-4=0
x^2+8x+?=4+?
In completeing the square method, you divide the coeficient of x by 2, square the result and add to both sides of the equation.
Therefore, he should add 16 to both sides because (8/2)^2=16.
option d.
</span>
option b.
Part 2:
option d
Part 3:
Multiply through by the LCM of 2 and 3 (i.e. 6)
option b
Part 4
x^2-3x-8=x+4
option d
Part 5
Joseph is solving the equation x^2+8x-4=0 using the technique completing the square.
x^2+8x-4=0
x^2+8x+?=4+?
In completeing the square method, you divide the coeficient of x by 2, square the result and add to both sides of the equation.
Therefore, he should add 16 to both sides because (8/2)^2=16.
option d.
</span>
Answer:
Explanation:
The order of the letters naming the triangles is relevant. When it is said that <em>triangle ABC is similar to triangle MOP</em>, means that:
- ∡A ≅ ∡M
- ∡B ≅ ∡O
- ∡C ≅ ∡P
Therefore:
- ∡A = 45º (given)
- ∡P = 102º (given)
- ∡C = 102º (by substitution)
Now, you have two angles of triangle ABC and can find the third one:
- ∡A + ∡B + ∡C = 180º
- ∡B = 180º - ∡A - ∡B
- ∡B = 180º - 45º - 102º = 33º ← answer