<h2>
<em><u>HEYA</u></em></h2>
<h3>THE MID TERM SPLITTING OF THE EQUATION IS :</h3>
now shifted to 5 units left
therefore,
x=-4
hope it helps you mate thanks for the question and if possible please mark it as brainliest
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
2
Step-by-step explanation:
We are asked to perform the subtraction
x² + xy - 3y² - (5x² - xy + y²) ← distribute the parenthesis by - 1
= x² + xy - 3y² - 5x² + xy - y² ← collect like terms
= (x² - 5x²) + (xy + xy) + (- 3y² - y² )
= - 4x² + 2xy - 4y²
Answer:
The gradient is 3/7 make y the subject. Then put the coordinates in the equation.
Step-by-step explanation:
Answer:
Step-by-step explanation:
AC = length of flagpole = 12 ft
AB = length of shadow = 14 ft
BC = length from the top of the flagpole to the end of the shadow = x ft
Use Pythagorean theorem to find the length of x,
x² = AC² + BC²
= 12² + 14²
= 144 + 196
= 340
x = √340
x = 18.4 ft
