The original price would have been $312.5
Answer:
Step-by-step explanation:
1.
sum > 8 or 9,10,11,12
events sum >8 are 36,45,54,63,46,55,64,56,65,66
no. of events=10
p=10/36=5/18
2.
P=291/2237
3.

4.
a.
P=5/246
b.
p=208/246=104/123
5.
yes no total
student 56 42 98
teacher 3 7 10
total 59 49 108
Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
We would divide $204 by 3 to find out how much did each shopper spent. $204/3 is $68. So, each shopper spent $68. Hope this helped!
2 1/3. 3 inches by 2 1/3 inches is 7. A 3rd of that is 2 1/3 or 2.3333333333