Which only lists multiples of 16? O1,2,4, 8, 16 O 16, 24, 32, 40 O16, 32, 48, 64 O 1,2, 4, 8, 12, 16
schepotkina [342]
Answer:
48 & 68
Step-by-step explanation:
if you multiply the numbers you will see that you get 48 & 68 multiple times
Answer:
v=6
Step-by-step explanation:
2v is positive so keep it
then 2v=12
v=6
Answer:28.6
I started by seeing how many 2.4 can go into 68.64. I found that it is pretty easy to find that if you multiply the 2.4 by ten you get 24 so we do that twice and have 48. We then subtract 48 from the 68.64 which leaves us with 20.64. If we multiply 2.4 by 5 we get 12 so once again subtract 12 from that 20.64 and now we are left with 8.64. So now we need to figure out how many more 2.4 are left well it is more than three because three gives us 7.2 so let’s subtract that from it now we are left with 1.44. Now we need to find out what times 2.4 gives us 1.44. Well it would be .6. So now if we add up everything we get the answer of 28.6. Sorry if this very complicated
Answer:
- ABCD is a rhombus, and a parallelogram
==================================
<h3>Given </h3>
- Points A(-6, - 1), B(4, - 6), C(2, 5), D(- 8, 10)
First, plot the points (see attached picture).
Then, connect all the points.
<h3>We see that:</h3>
- Opposite sides are parallel,
- Diagonals are perpendicular.
From our observation the figure is rhombus.
Let's confirm it with the following.
1) Find midpoints of diagonals and compare.
- AC → x = (- 6 + 2)/2 = - 2, y = (- 1 + 5)/2 = 2
- BD → x = (4 - 8)/2 = - 2, y = (- 6 + 10)/2 = 2
The midpoint of both diagonals is same (- 2, 2).
2) Find slopes of diagonals and check if their product is -1, this will confirm they are perpendicular.
- m(AC) = (5 - (-1))/(2 - (-6)) = 6/8 = 3/4
- m(BD) = (10 - (-6))/(-8 - 4) = - 16/12 = - 4/3
- m(AC) × m(BD) = 3/4 * (- 4/3) = - 1
<u>Confirmed.</u>
So this is a rhombus and also a parallelogram but <u>not</u> rectangle or square, since opposite angles are not right angles.
Answer:
t(g)= -4g + 20
Step-by-step explanation:
James is playing his favorite game at the arcade. After playing the game 3 times, he has 8 tokens remaining. He initially had 20 tokens, and the game costs the same number of tokens each time. The number tt of tokens James has is a function of gg, the number of games he plays
Solution
Let
g=No. of games James plays
t= No. of tokens James has.
Find the slope using
y=mx + b
Where,
m = Slope of line,
b = y-intercept.
Before James started playing the games, he has a total of 20 tokens.
That is, when g=0, t=20
After James played the games 3 times, he has 8 tokens left
That is, when g=3, t=8
(x,y)
(0,20) (3,8)
m=y2-y1 / x2-x1
=(8-20) / (3-0)
= -12 / 3
m= -4
Slope of the line, m= -4
y=mx + b
No. of tokens left depend on No. of games James plays
t is a function of g.
t(g)
t(g)= -4g + 20
