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3 years ago

What is the square root of 0.49 A.49/7 B.49/10 C.10/7 D.7/10

Mathematics

2 answers:

aliya0001 [1]3 years ago

6 0

Answer:

Step-by-step explanation:

I think that it would be d

posledela3 years ago

6 0

Answer:

<h2>option D</h2>

Step-by-step explanation:

hope it helps..........

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On the coordinate plane below, Point P is located at (2,-3), and point Q is located at (-4,4).

Semenov [28]

Answer:

Approximately 9 units.

Step-by-step explanation:

To find the distance between two ordered pairs, we can use the distance formula. The distance formula is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let (2,-3) be x₁ and y₁ respectively, and let (-4,4) be x₂ and y₂, respectively.

$d=\sqrt{(-4-2)^2+(4--3)^2} \\d=\sqrt{(-6)^2+(7)^2} \\d=\sqrt{36+49} \\d=\sqrt{85}\approx9$

7 0

3 years ago

PLEASE HELP ME!!!!!!!!!

vitfil [10]

$(x - 4) {}^{2} - 28 = 8 \\ (x - 4) {}^{2} = 8 + 28 \\ (x - 4) {}^{2} = 36$

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

$\sqrt{(x - 4) {}^{2} } = ± \sqrt{36} \\x - 4 = ±6 \\ x _{1}- 4 = 6 \: \: \: \: \: \: \: \: \: \: x _{2}- 4 = - 6 \\ x_{1} = 6 + 4 \: \: \: \: \: \: \: \: \: \: x_{2} = - 6 + 4 \\ x_{1} = 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x_{2} = - 2$

Well he started off correct to the point of completing the square.

$(x - 3) {}^{2} = 16 \\ x - 3 = ±4 \\ \: x_{1} - 3 = 4 \: \: \: \: \: \: \: \: \: \: \: \: x_{2} - 3 = - 4 \\ x_{1} = 7 \: \: \: \: \: \: \: \: \: \: x_{2} = - 1$

8 0

10 months ago

a survey of 153 law firms in a coutry found that the aveage hourly billing roate for partners is 642 what is the population

Art [367]

Answer:

Population, well, it is recorded as partners and 642x153=98226 is calculated correctly, you divided by 2 which is 98226 divided by 2 is 49113.

8 0

2 years ago

How would the factor pairs change if nancy had only 5 posters to arrange?

Romashka [77]

Answer:

Part A) Nancy can arrange the posters in 4 ways

Part B) Nancy can arrange the posters in 2 ways

Step-by-step explanation:

<u><em>The complete question is</em></u>

Nancy has 10 movie posters. She wants to hang them on a wall in equals rows.

A) Find all the ways that she can arrange the posters.

B) How would the factor pairs change if Nancy had only 5 posters to arrange?

Part A) Find all the ways that she can arrange the posters.

we know that

The factors of 10 are

1x10 -----> 1 row of 10 posters

2x5 -----> 2 rows of 5 posters

5x2 -----> 5 rows of 2 posters

10x1 -----> 10 rows of 1 poster

therefore

Nancy can arrange the posters in 4 ways

Part B) How would the factor pairs change if Nancy had only 5 posters to arrange?

we know that

if Nancy had only 5 posters to arrange

then

The factors of 5 are

1x5 -----> 1 row of 5 posters

5x1 -----> 5 rows of 1 poster

therefore

Nancy can arrange the posters in 2 ways

3 0

3 years ago

I’ll give brainliest

melomori [17]

Answer:

a.No

b.-7/2, it is at (4,-7/2)

c.-5?4, it is at (2,-5/4)

d.All real numbers except 6

e.3

f.-1/2

Step-by-step explanation:

a. Plug it in! f(5)=((5)+3)/((5)-6)=-8, so no!

b. Plug it in! f(4)=((4)+3)/((4)-6)=-7/2

c. Plug it in! f(2)=((2)+3)/((2)-6)=-5/4

d. If it were to be 6, then it would be 3/0 which would be undefined.

d.f(-3)=((-3)+3)/((-3)-6))=0/8

f.f(0)=((0)+3)/((0)-6)=-1/2

6 0

2 years ago