Answer:
{-1, 2}
Step-by-step explanation:
The quantity x + 1 changes sign at x = -1; equivalently, x + 1 = 0 when x = -1.
If x = -1, then |x+1|+|x−2|=3 becomes |-1 + 1| + |-1 −2|=3, which is TRUE. So x = -1 is a solution.
If x = 2, then we have the equation |2 + 1| + |2 − 2|=3, or |2 + 1| = 3, which is TRUE. So x = 2 is also a solution.
You multiply the two together
x times x equals x squared ( x^2) the x times 2 which equals 2x, then multiply the 3 and x to get 3x and multiply 3 times 2 = 6
so now your problem looks like x[tex] x^{2} + 2x +3x +6 ( now combine like terms) which gives you x^{2} +5x +6, and thats the answer
Answer:
Step-by-step explanation:
Given
Required
Determine a homogeneous linear differential equation
Rewrite the expression as:
Where
and 
For a homogeneous linear differential equation, the repeated value m is given as:
Substitute values for 
and 
Add 1 to both sides
Square both sides
In complex numbers:
So, the expression becomes:
Add 1 to both sides
This corresponds to the homogeneous linear differential equation
I think the answer should be
