1750 N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and

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1750 N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and

weighing 0.290 N. The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached. If you pluck both strings at the same time at the beam, what is the time delay between the arrival of the two pulses at the ceiling

Physics

1 answer:

Arturiano [62] · Answer 1 · 2023-04-30T03:35:22+03:00

The time delay between the arrival of the two pulses at the ceiling is 2.33 ms.

<h3>What is center of gravity?</h3>

Any object of mass is attracted towards another by point where whole mass is supposed to be concentrated is called center of gravity.

A 1750 N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and weighing 0.290 N.

The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached.

Taking moments about one end, to find the tension at other end.

Tb X L = WxL/3

here, W is the weight, L is the length of wire and Tb is the tension at point B.

So, Tb = W/3

and
Tb - Ta = W

here, Ta is the tension in end A.

Substitute the values, we get

Tb = 583.33N and Ta = 1166.66N

Velocity of end A, Va = (1166.66 x1.25 x 9.81/0.290 )^(1/2)

Va = 222 m/s

Velocity of end B, Vb = (583.33 x1.25 x 9.81/0.290 )^(1/2)