Jack travelled 360 km at an average speed of 80 km/h. Elaine took 1.5 hours more to complete the same amount of distance. What w
1 answer:
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Answer:
discharge rate (Q) = 0.2005 m^{3} / s
Explanation:
if you read the question you would see that some requirements are missing, by using search engines, you can get the complete question as stated below:
Water flows steadily from an open tank as shown in the figure. (Figure 1) The elevation of point 1 is 10.0m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80x10-2m ; at point 3, where the water is discharged, it is 1.60x10-2m. The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. Part A Assuming that Bernoulli's equation applies, compute the volume of water DeltaV that flows across the exit of the pipe in 1.00 s . In other words, find the discharge rate \Delta V/Delta t. Express your answer numerically in cubic meters per second.
solution:
time = 1 s
elevation of point 1 (z1) = 10 m
elevation of point 2 (z2) = 2 m
elevation of point 3 (z3) = 2 m
cross section area of point 2 = 4.8 x 10^{2} m
cross section area of point 3 = 1.6 x 10^{2} m
g
acceleration due to gravity (g) = 9.8 m/s^{2}
find the discharge rate at point 3 which is the exit pipe.
discharge rate (Q) = A3 x V3
where A3 is the cross sectional area at point 3 and V3 is the velocity of the fluid and can be gotten by applying Bernoulli's equation below
pressure at point 1 (P1) is the same as pressure at point 3 (P3), and at point 1, the velocity (V1) = 0. therefore the equation now becomes
V3 =
V3 =
V3 = 12.53 m/s
discharge rate (Q) = A3 x V3 = 1.6 x 10^{-2} x 12.53
discharge rate (Q) = 0.2005 m^{3} / s
Answer:
B) Angular velocity
Explanation:
The equivalent of Newton's second law for the rotational motions can be written as:
where
is the net torque applied to the object
I is the moment of inertia
is the angular acceleration
From the formula we see that when a constant net torque is applied, then the object also has a constant angular acceleration,
.
But we also know that
where is the angular velocity: so, a constant angular acceleration means that the angular velocity of the object is changing, so the correct answer is
B) Angular velocity
(moment of inertia and center of gravity do not change since they only depend on the mass and the geometry/shape of the object, which do not change)
According to Newton's second law, the resultant of the forces acting on the box is equal to the product between its mass and its acceleration:
(1)
we are only concerned about the horizontal direction, so there are only two forces acting on the box in this direction:
- the horizontal component of the force exerted by the rope, which is equal to
- the frictional force, acting in the opposite direction, which is equal to
By applying Newton's law (1), we can calculate the acceleration of the box:
we are only concerned about the horizontal direction, so there are only two forces acting on the box in this direction:
- the horizontal component of the force exerted by the rope, which is equal to
- the frictional force, acting in the opposite direction, which is equal to
By applying Newton's law (1), we can calculate the acceleration of the box: