Question

Show and/or explain that sin C = sin(A+B) in any & ABC.

Answer 1

$\text{In any triangle ABC,}~\\\\A +B+C = \pi\\\\\text{Now,}\\\\\text{L.H.S}\\\\=\sin C\\\\=\sin\left[\pi - (A+B) \right]\\\\=\sin(A+B)\\\\=\text{R.H.S}\\\\\text{Showed.}$