She invested $11,250 in the stock, $3,750 in the CD and $12,000 in the bond fund.
<h3><u>Distributions</u></h3>
Given that Sylvia invested a total of $27,000, and she invested part of the money in a certificate of deposit (CD) that earns 3% simple interest per year, she invested in a stock that returns the equivalent of 7% simple interest, and she invested in a bond fund that returns 2%, and she invested three times as much in the stock as she did in the CD, and earned a total of $1140 at the end of 1 yr, to determine how much principal did she put in each investment, the following calculation must be made:
- 9000 x 0.07 + 3000 x 0.03 + 15000 x 0.02 = 630 + 90 + 300 = 1020
- 9900 x 0.07 + 3300 x 0.03 + 13800 x 0.02 = 693 + 99 + 276 = 1068
- 12,000 x 0.07 + 4,000 x 0.03 + 11,000 x 0.02 = 840 + 120 + 220 = 1,180
- 11400 x 0.07 + 3800 x 0.03 + 11800 x 0.02 = 798 + 114 + 236 = 1148
- 10800 x 0.07 + 3600 x 0.03 + 12600 x 0.02 = 756 + 108 + 252 = 1116
- 11160 x 0.07 + 3720 x 0.03 + 12120 x 0.02 = 781.2 + 111.6 + 242.4 = 1135.2
- 11190 x 0.07 + 3730 x 0.03 + 12080 x 0.02 = 783.3 + 111.9 + 241.6 = 1136.8
- 11250 x 0.07 + 3750 x 0.03 + 12000 x 0.02 = 787.5 + 112.5 + 240 = 1140
Therefore, she invested $11,250 in the stock, $3,750 in the CD and $12,000 in the bond fund.
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Answer:
just take speed =distance ÷time
dustance is speedxtime
14x1.61=22.54÷60 to change to min =0.37km per minute
0.40x0.37= 0.148 km
perhaps I may get wrong
The slope is:
.
________________________________________________________Note:________________________________________________________slope = rise/ run = 15 ft/ 1000 ft ;
= 15/1000 = (15÷15) / (1000÷15) ;
= 1/ (200/3) = 1* (3/200) =
[tex] \frac{3}{200} [/tex] .
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B. 4 1/4 <_ 2K because the point of the arrow is going to the less amount and when you ad the line under it, that makes it equal to or less than. In other words no more than.
