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2 years ago

martina must choose a number between 49 and 95 that is multiple of 2,8 and 10. write all the numbers that she could choose.

Mathematics

1 answer:

gtnhenbr [62]2 years ago

6 0

Answer:

Step-by-step explanation:

10 limits it to 50, 60, 70, 80, and 90

2 eliminates none since 50=25, 60=30, 70=35, 80=40 and 90=45

8 divided by each number only leaves one option of 80. (80/8= 10) (80/10=8) (80/2=40)

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Bo and Erica are yoga instructors. Between the two of them, they teach 45 yoga classes each week. If Erica teaches 15 fewer than

Solnce55 [7]

Answer:

20 and 25.

Step-by-step explanation:

Given:

They both teach total 45 yoga classes each week.

Erica teaches 15 fewer than twice as many as Bo.

To find:

How many classes does each instructor teach per week = ?

Solution:

Let number of classes are taken by Bo = $x$

Then number of classes are taken by Erica = $2x - 15$ (given)

Total number of classes are taken by both = 45 (given)

According to the question.

$x$ + $2x - 15$ = 45

$3x - 15 = 45$

By adding both side by 15

$3x = 60\\$

By dividing both side by 3

$x = 20$

number of classes are taken by Bo = $x$ = 20

number of classes are taken by Erica = $2x - 15$

= $2\times20 - 15 = 40- 15 = 25\\$

Therefore, number of classes are taken by Bo and Erica is 20 and 25.

6 0

3 years ago

Question is on picture attached

nalin [4]

$7(\frac{9}{4}x- \frac{18}{7})= -\frac{5}{21} +\frac{17}{7}x \frac{63}{4}x-18 =-\frac{5}{21}+ \frac{17}{7}x\\ \frac{63}{4}x - \frac{17}{7}x = 18-\frac{5}{21}\frac{373}{28} =\frac{373}{21} x=\frac{4}{3}$

ok done. Thank to me :>

5 0

2 years ago

PLEASE HELP BEST ANSWER ILL GIVE BRAINLIEST!!

MrRa [10]

It’s b) an =-125(-^2/5)^n

4 0

3 years ago

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ <em>cross multiply</em>

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

2 years ago

Which of the following is the correct factorization of the polynomial below?

alexandr1967 [171]

X + 7 might be right

8 0

3 years ago