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kondor19780726 [428]
3 years ago
5

Solve for y. y - 3x = 1

Mathematics
2 answers:
Burka [1]3 years ago
5 0

Answer:

y = 1 + 3x

Step-by-step explanation:

You move everything from the the side with what you are trying to solve to the other side.

Because you have both x and y this is the simplest form.

Marat540 [252]3 years ago
4 0

Answer:

Original equation: y-3x=1

Add 3x to both sides, which would isolate y: y=3x+1

Let me know if this helps!

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Place the indicated product in the proper location on the grid. (4x^3+7y^3 z^ 4) ^2
ella [17]

Answer:

16x^{6} +56x^{3}y^{3} z^{4} +49y^{6} z^{8} \\

Step-by-step explanation:

To solve this type of problems first need to review some laws of exponents:

When you are multiplying the same base, you need to add the exponents.

x^{2} +x^{8}  = x^{2+8}  = x^{10}

When you are raising a base with power to another power, you should keep the base and multiply the exponents:

(x^{2} y^{5})^3 = x^{2*3} y^{5*3} = x^{6} y^{15}

Now for the expression (4x^{3} + 7y^{3} z^{4} )^2

Write the multiplying factors:

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} )

Multiply the term 4x^{3}

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}

Then multiply the term 7y^{3}z^{4}

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{3+3} z^{4+4}

Simplify the exponents:

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{6} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{6} z^{8}

Add like terms:

= 16x^{6} + 56x^3y^{3} z^{4} + 49y^{6} z^{8}

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3 years ago
Dwight has a new job that garuntees a six percent raise of each year with the company. His initial salary $52,000 per year
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Answer:

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Step-by-step explanation:

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2 years ago
I need help with math homework
kobusy [5.1K]

Answer:

A. (0, 1) and (2, -2)

B. Slope (m) = -³/2

C. y + 2 = -³/2(x - 2)

D. y = -\frac{3}{2}x + 1

E. \frac{3}{2}x + y = 1

Step-by-step explanation:

A. Two points on the line from the graph are: (0, 1) and (2, -2)

B. The slope can be calculated using two points, (0, 1) and (2, -2):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-2 - 1}{2 - 0} = \frac{-3}{2} = -\frac{3}{2}

Slope (m) = -³/2

C. Equation in point-slope form is represented as y - b = m(x - a). Where,

(a, b) = any point on the graph.

m = slope.

Substitute (a, b) = (2, -2), and m = -³/2 into the point-slope equation, y - b = m(x - a).

Thus:

y - (-2) = -³/2(x - 2)

y + 2 = -³/2(x - 2)

D. Equation in slope-intercept form, can be written as y = mx + b.

Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.

y + 2 = -³/2(x - 2)

2(y + 2) = -3(x - 2)

2y + 4 = -3x + 6

2y = -3x + 6 - 4

2y = -3x + 2

y = -3x/2 + 2/2

y = -\frac{3}{2}x + 1

E. Convert the equation in (D) to standard form:

y = -\frac{3}{2}x + 1

\frac{3}{2}x + y = 1

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