6^6??????? please help meeeee

Detetmine the next two terms in the sequence.

iragen [17]

Detetmine the next two terms in the sequence.
3, 16, 29, 42,
21, 25, 29, 33,
1, 2, 3, 5, 8, 1,

Determine the missing number in each sequence.

5,____, 10, 12 1/2
11, 5, 9, 4,____, 5, 2
40, ____, 37 1/3, 36

4 0

3 years ago

For which intervals is the function decreasing?

lilavasa [31]

Answer:

The function is decreasing in the following intervals

A. (0, 1)

C. (2, pi)

Step-by-step explanation:

To answer this question, imagine that you draw lines of slope m parallel to the function shown at each point.

-If the slope of this line parallel to the function is negative for those points then the function is decreasing.

-If the slope of this line parallel to the function is positive for those points then the function is increasing.

Observe in the lines drawn in the attached image. You can see that they have slope less than zero in the following interval:

(0, 1) U (2, pi)

Therefore the correct option is:

A. (0, 1)

C. (2, pi)

5 0

3 years ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

So

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$