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Nana76 [90]
2 years ago
11

Rita has 3/4 gallon of lemonade she pours 1/24 gallon of lemonade into each glassk Rita has 3/4 gallons of lemonade she pours on

e 24 gallon of lemonade into each glass how many glasses of lemonade can she pour
Mathematics
1 answer:
ira [324]2 years ago
8 0

Answer:

18 number of glasses of lemonade can she pour

Step-by-step explanation:

Unit rate defined as rates are expressed as a quantity of 1, such as 3 feet per second or 8 miles per hour, they are called unit rates.

As per the statement: Rita has 3/4 gallon of lemonade she pours 1/24 gallon of lemonade into each glass.

Number of lemonade Rita has  = 3/4 gallon

\text{Unit rate per glass} = \frac{1}{24} \text{gallons}

By definition of unit rate;

\text{Number of glasses} = \frac{\text{Number of lemonade}}{\text{Unit rate per glass}}

Substitute the given values we get;

\text{Number of glasses} = \frac{\frac{3}{4}}{\frac{1}{24}}

\text{Number of glasses} = \frac{3}{4} \times 24 = 3 \times 6 = 18

Therefore, number of glasses of lemonade can she pour is, 18




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(2,4)

Step-by-step explanation:

We have the system:

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I'm going to replace my first y with what the second y equals.

That is, I'm going to write 3x-2=x+2.

Time to solve the following for x:

3x-2=x+2

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Divide both sides by 2:

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Now that we know x=2 and we have an equation that relates x to y: either y=x+2 or y=3x-2, doesn't matter which we use, we can find y.

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In the game of​ roulette, a player can place a ​$9 bet on the number 11, and have a 1/38 probability of winning. If the metal ba
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Answer:

1. What is the expected value of the game to the​ player?

Expected value= -$0.47368

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value= -$473.68

Step-by-step explanation:

1. What is the expected value of the game to the​ player?

Expected value can tell how much you will gain/lose every time you do the game. To find the expected value you need to multiply every value with its chance to occur. There are two types of events here, winning and losing. You have 1/38 chance of winning $315 and 37/38 chance of losing $9.  

The expected value will be:

expected value= 1/38 * $315 + 37/38*(-$9) = $8.2894 - $8.7631

expected value= -$0.47368

You are expected to lose $0.47368 every time you play

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value calculated for each roll. If you want to know how much you gain/lose by multiple rolls, you just need to multiply the expected value with the number of rolls. The game has negative expected value so you are expected to lose money instead of gaining money. The money you expected to lose will be:

number of roll * expected value

1000 timer * -$0.47368/time= -$473.68

You are expected to lose $473.68 if you play the game 1000 times.

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