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Nana76 [90]
3 years ago
11

Rita has 3/4 gallon of lemonade she pours 1/24 gallon of lemonade into each glassk Rita has 3/4 gallons of lemonade she pours on

e 24 gallon of lemonade into each glass how many glasses of lemonade can she pour
Mathematics
1 answer:
ira [324]3 years ago
8 0

Answer:

18 number of glasses of lemonade can she pour

Step-by-step explanation:

Unit rate defined as rates are expressed as a quantity of 1, such as 3 feet per second or 8 miles per hour, they are called unit rates.

As per the statement: Rita has 3/4 gallon of lemonade she pours 1/24 gallon of lemonade into each glass.

Number of lemonade Rita has  = 3/4 gallon

\text{Unit rate per glass} = \frac{1}{24} \text{gallons}

By definition of unit rate;

\text{Number of glasses} = \frac{\text{Number of lemonade}}{\text{Unit rate per glass}}

Substitute the given values we get;

\text{Number of glasses} = \frac{\frac{3}{4}}{\frac{1}{24}}

\text{Number of glasses} = \frac{3}{4} \times 24 = 3 \times 6 = 18

Therefore, number of glasses of lemonade can she pour is, 18




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The answer is d<span>iscrete.</span>
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There were 200 melons in a box and they were distributed to 3 children in the ratio of 4:3:3. The first child sold the melons at
Elena L [17]

Answer:

$460

Step-by-step explanation:

let the number of melons be x

4x + 3x + 3x = 200 melons

10x = 200 so, x will be 20

4x = 80 melons

3x = 60

3x = 60

amount made by 1st child = 80 × $2 = 160$

the remaining melons are 60 + 60 = 120

amount collected: they sold them in groups of 2 and each group was $5. so,

120÷2 × $5 = $300

total amount = 300 + 160 = $460.

6 0
4 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.
devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0
3 years ago
5,930,000 in scientific notation
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Answer:

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5.93 is the decimal of 5,930,000

there are 4 zeros so it leads to 10 to the 4th power

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The HCF of two number is 40 and their product is 52800. find their lcm​
Dima020 [189]

Answer: 1320

Step-by-step explanation:

Given,

HCF of two numbers = 40

Product of two numbers = 52800

To find,

LCM of two numbers =?

Formula required,

HCF × LCM = product of two numbers

Calculation,

Using formula

→ HCF × LCM = product of two numbers

→ ( 40 ) × LCM = 52800

→ LCM = 52800 / 40

→ LCM = 1320

Therefore,

LCM of two numbers would be 1320.

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